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The battery in an electric car needs to be recharged - AQA - GCSE Physics - Question 8 - 2022 - Paper 1

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The battery in an electric car needs to be recharged. Suggest two factors that affect the distance an electric car can travel before the battery needs to be recharg... show full transcript

Worked Solution & Example Answer:The battery in an electric car needs to be recharged - AQA - GCSE Physics - Question 8 - 2022 - Paper 1

Step 1

Suggest two factors that affect the distance an electric car can travel before the battery needs to be recharged.

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Answer

  1. Capacity of the battery.
  2. Efficiency of the battery.

Step 2

Write down the equation which links acceleration (a), change in velocity (Δv) and time taken (t).

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Answer

The equation is:

a=Δvta = \frac{\Delta v}{t}

Step 3

Calculate the time taken for the speed of the car to change from 0 m/s to 28 m/s at its maximum acceleration.

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Answer

Using the equation of motion:

a=Δvta = \frac{\Delta v}{t}

Substituting the values:

20=280t20 = \frac{28 - 0}{t}
Solving for t gives:

t=2820=1.4 st = \frac{28}{20} = 1.4 \text{ s}

Step 4

Calculate the final velocity of the car.

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Answer

Using the equation of motion:

v2=u2+2asv^2 = u^2 + 2as

Where:

  • Initial velocity, u=0u = 0 m/s,
  • Acceleration, a=10a = 10 m/s²,
  • Distance, s=605s = 605 m.

Substituting the values gives:

v2=0+2×10×605v^2 = 0 + 2 \times 10 \times 605
v2=12100v^2 = 12100
v = 110 m/s

Step 5

Write down the equation which links distance (s), force (F) and work done (W).

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Answer

The equation is:

W=F×sW = F \times s

Step 6

Calculate the work done against air resistance when the car travels a distance of 7.5 km at its maximum speed.

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Answer

First, convert 7.5 km to meters:
7.5 km = 7500 m.

Using the equation:

W=F×sW = F \times s Substituting the values gives:

W=4000N×7500m=30000000JW = 4000 N \times 7500 m = 30000000 J

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