During a different part of the journey the car accelerates from 9 m/s to 18 m/s in 6 s - AQA - GCSE Physics - Question 10 - 2018 - Paper 1
Question 10
During a different part of the journey the car accelerates from 9 m/s to 18 m/s in 6 s.
Use the following equation to calculate the acceleration of the car.
acceler... show full transcript
Worked Solution & Example Answer:During a different part of the journey the car accelerates from 9 m/s to 18 m/s in 6 s - AQA - GCSE Physics - Question 10 - 2018 - Paper 1
Step 1
Use the following equation to calculate the acceleration of the car.
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Answer
To find the acceleration, we use the formula:
extacceleration=time takenchange in velocity.
Given that the initial velocity is 9 m/s and the final velocity is 18 m/s:
Change in velocity = Final velocity - Initial velocity = 18 m/s - 9 m/s = 9 m/s
Time taken = 6 s
Thus,
acceleration=6 s9 m/s=1.5 m/s2.
Step 2
Which equation links acceleration, mass and resultant force?
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Answer
The correct equation that links acceleration, mass, and resultant force is:
resultant force = mass x acceleration.
Step 3
Calculate the resultant force acting on the car and driver while accelerating.
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Answer
To calculate the resultant force, we first need to find the total mass:
Total mass = Mass of the car + Mass of the driver = 1120 kg + 80 kg = 1200 kg.
Using the formula:
F=m×a,
where the mass (m) is 1200 kg and the acceleration (a) is 1.5 m/s²:
F=1200 kg×1.5 m/s2=1800 N.
Therefore, the resultant force is 1800 N.
Step 4
Explain what happens to the braking distance if the speed doubles.
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Answer
When the speed of the car doubles, the kinetic energy increases by a factor of 4.
This is because kinetic energy (KE) is given by the formula:
KE=21mv2,
where m is mass and v is velocity.
If the speed doubles, the new kinetic energy becomes:
KEnew=21m(2v)2=2mv2=4×KEoriginal.
Since the braking force remains constant, the increased kinetic energy requires a longer stopping distance. Therefore, if the speed doubles, the braking distance also increases by a factor of 4.