This question is about properties of materials - Edexcel - GCSE Chemistry Combined Science - Question 7 - 2016 - Paper 1
Question 7
This question is about properties of materials.
Figure 6 shows some properties of steel and Kevlar®:
| property | steel | Kevlar® |
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Worked Solution & Example Answer:This question is about properties of materials - Edexcel - GCSE Chemistry Combined Science - Question 7 - 2016 - Paper 1
Step 1
Calculate the surface area to volume ratio of this cube of silver.
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Answer
To calculate the surface area to volume ratio, we need to first determine the surface area and the volume of the cube:
Surface Area: The formula for the surface area (SA) of a cube is given by:
SA=6a2
where a is the length of one side. For this cube, a = 2 cm:
SA=6(22)=6(4)=24extcm2
Volume: The formula for the volume (V) of a cube is:
V=a3
Using the same side length:
V=23=8extcm3
Surface Area to Volume Ratio: Finally, the surface area to volume ratio (SA:V) is calculated as follows:
SA:V=VSA=8extcm324extcm2=3extcm−1
Thus, the surface area to volume ratio is 3 cm⁻¹.
Step 2
Suggest an explanation of why a given mass of silver is more effective as a catalyst when used as nanoparticles rather than in a powder form.
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Answer
When silver is used as nanoparticles, it has a significantly higher surface area to volume ratio compared to its powdered form. This increased surface area allows more active sites for catalytic reactions to occur.
With nanoparticles:
The number of particles is larger compared to a bulk form, leading to a higher surface area available for reactions.
There is better accessibility for reactants to reach the catalytic sites.
In contrast, powdered silver has fewer active sites exposed, which results in a lower rate of reaction due to decreased collision frequency between reactants and the catalyst. Therefore, utilizing silver in nanoparticle form enhances its effectiveness as a catalyst.