A student used the apparatus in Figure 1 to investigate the rate of the reaction between a metal and dilute hydrochloric acid. Pieces of the metal were placed in dilute hydrochloric acid in the flask, and the total volume of gas produced was measured every minute. (a) Figure 2 shows a graph of the student’s results. Figure 2 Graph showing volume of hydrogen (in cm³) against time (in minutes).

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A student used the apparatus in Figure 1 to investigate the rate of the reaction between a metal and dilute hydrochloric acid - Edexcel - GCSE Chemistry Combined Science - Question 1 - 2022 - Paper 1

Question 1

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A student used the apparatus in Figure 1 to investigate the rate of the reaction between a metal and dilute hydrochloric acid. Pieces of the metal were placed in di... show full transcript

Worked Solution & Example Answer:A student used the apparatus in Figure 1 to investigate the rate of the reaction between a metal and dilute hydrochloric acid - Edexcel - GCSE Chemistry Combined Science - Question 1 - 2022 - Paper 1

Step 1

What is the more suitable piece of apparatus to measure the total volume of gas produced?

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Answer

The more suitable piece of apparatus to measure the total volume of gas produced is a 100 cm³ measuring cylinder. This choice is appropriate because it has smaller gradations, thus allowing for a more precise measurement of the gas volume.

Step 2

Calculate the rate of reaction at 90s.

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Answer

To calculate the rate of reaction at 90 seconds, we can use the formula:

$\text{Rate} = \frac{\text{volume of gas}}{\text{time}}$

From the graph, at 90 seconds the volume of hydrogen produced is 29 cm³. Therefore:

$\text{Rate} = \frac{29 \text{ cm}^3}{90 \text{ s}} \approx 0.322 \text{ cm}^3 \, \text{per second}$

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