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The word equation for the reaction between magnesium and dilute hydrochloric acid is magnesium + hydrochloric acid → magnesium chloride + hydrogen The reaction was carried out using the apparatus shown in Figure 6 - Edexcel - GCSE Chemistry Combined Science - Question 4 - 2019 - Paper 1

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Question 4

The-word-equation-for-the-reaction-between-magnesium-and-dilute-hydrochloric-acid-is--magnesium-+-hydrochloric-acid-→-magnesium-chloride-+-hydrogen--The-reaction-was-carried-out-using-the-apparatus-shown-in-Figure-6-Edexcel-GCSE Chemistry Combined Science-Question 4-2019-Paper 1.png

The word equation for the reaction between magnesium and dilute hydrochloric acid is magnesium + hydrochloric acid → magnesium chloride + hydrogen The reaction was... show full transcript

Worked Solution & Example Answer:The word equation for the reaction between magnesium and dilute hydrochloric acid is magnesium + hydrochloric acid → magnesium chloride + hydrogen The reaction was carried out using the apparatus shown in Figure 6 - Edexcel - GCSE Chemistry Combined Science - Question 4 - 2019 - Paper 1

Step 1

4(b) Describe the gas that is formed.

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Answer

The gas produced in the reaction is hydrogen. This can be inferred from the word equation provided, which indicates that hydrogen gas is one of the products formed when magnesium reacts with dilute hydrochloric acid.

Step 2

4(c) Explain why the mass of the flask decreases.

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Answer

The mass of the flask decreases because hydrogen gas is released into the atmosphere during the reaction. As the magnesium ribbon reacts with the hydrochloric acid, it produces magnesium chloride and hydrogen gas. Since the gas escapes the closed system, the total mass of the flask and its contents is reduced.

Step 3

4(d) Calculate the volume of hydrogen gas produced after 5 minutes.

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To find the volume of hydrogen gas produced, we can refer to the data shown in Figure 7. At 5 minutes, the loss in mass of the flask is approximately 0.008 g. Given that 1 mole of hydrogen gas (H₂) has a molar mass of about 2 g, we can calculate the volume of gas produced using the ideal gas laws and standard conditions, where 1 mole of gas occupies 24,000 cm³. Therefore, the volume of hydrogen produced can be determined by:

Volume=mass of H2molar mass of H2×24000Volume = \frac{mass\ of\ H_2}{molar\ mass\ of\ H_2} \times 24000

Substituting the values:

Volume=0.008 g2 g/mol×24000=96 cm3Volume = \frac{0.008 \text{ g}}{2\text{ g/mol}} \times 24000 = 96 \text{ cm}^3

Step 4

4(e) Sketch a graph to show the expected results of the experiment.

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Answer

The graph should depict the loss in mass (in grams) on the y-axis against time (in minutes) on the x-axis. The curve should start at the origin and rise sharply at first, indicating a rapid reaction, and then level off as the reaction nears completion, resembling the graph shown in Figure 7. The gradient should decrease progressively.

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