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9 (a) Calcium carbonate reacts with dilute hydrochloric acid to produce carbon dioxide gas - Edexcel - GCSE Chemistry - Question 9 - 2020 - Paper 1

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9 (a) Calcium carbonate reacts with dilute hydrochloric acid to produce carbon dioxide gas. (i) The investigation was carried out with different sized calcium carbo... show full transcript

Worked Solution & Example Answer:9 (a) Calcium carbonate reacts with dilute hydrochloric acid to produce carbon dioxide gas - Edexcel - GCSE Chemistry - Question 9 - 2020 - Paper 1

Step 1

State, using the information in Figure 15, the effect of the surface area of the calcium carbonate on the rate of this reaction.

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Answer

The surface area of the calcium carbonate affects the rate of reaction. Smaller pieces of calcium carbonate have a larger surface area compared to larger pieces, which results in a higher rate of reaction. This is because more surface area allows more collisions between reactant particles, leading to an increased reaction rate.

Step 2

Calculate the average rate of reaction in cm³/s.

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Answer

To calculate the average rate of reaction, use the formula:

extRateofreaction=Volume of gas producedTime taken ext{Rate of reaction} = \frac{\text{Volume of gas produced}}{\text{Time taken}}

Substituting the values:

Rate of reaction=90 cm35 minutes\text{Rate of reaction} = \frac{90 \text{ cm}^3}{5 \text{ minutes}}

First, convert time from minutes to seconds:

5 minutes=5×60=300 seconds5 \text{ minutes} = 5 \times 60 = 300 \text{ seconds}

Now we can calculate:

Rate of reaction=90 cm3300 s=0.3 cm3/s\text{Rate of reaction} = \frac{90 \text{ cm}^3}{300 \text{ s}} = 0.3 \text{ cm}^3/s

Step 3

Explain, in terms of particles, why the rate of reaction increased when the temperature was increased.

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Answer

As the temperature increases, the particles gain more kinetic energy, which results in faster movement. When particles move faster, they collide more frequently with each other. This increase in collision frequency raises the likelihood that the collisions have sufficient energy to overcome the activation energy barrier, leading to a higher rate of reaction.

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