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5 (a) The diagram shows the structure of diamond - Edexcel - GCSE Chemistry - Question 5 - 2014 - Paper 1

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5 (a) The diagram shows the structure of diamond. (i) Describe what each ● represents. (ii) State the type of bonding in the diamond structure. (b) Give the name ... show full transcript

Worked Solution & Example Answer:5 (a) The diagram shows the structure of diamond - Edexcel - GCSE Chemistry - Question 5 - 2014 - Paper 1

Step 1

Describe what each ● represents.

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Answer

The ● represents a carbon atom. Each vertex of the structure in the diagram indicates a carbon atom within the diamond lattice.

Step 2

State the type of bonding in the diamond structure.

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Answer

The type of bonding in the diamond structure is covalent bonding.

Step 3

Give the name of the process used to obtain oxygen from liquid air.

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Answer

The process used to obtain oxygen from liquid air is fractional distillation.

Step 4

What is the Rf value of this dye?

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Answer

To calculate the Rf value, use the formula:

Rf=distance moved by dyedistance moved by solventRf = \frac{distance\ moved\ by\ dye}{distance\ moved\ by\ solvent}

Substituting the values, we have:

Rf=2cm8cm=0.25Rf = \frac{2 cm}{8 cm} = 0.25

Thus, the answer is A 0.25.

Step 5

Describe how the reaction can be carried out, including an explanation of what happens to the magnesium and oxygen atoms when they form magnesium oxide.

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Answer

To carry out the reaction, follow these steps:

  1. Ignite Magnesium: Place a strip of magnesium ribbon in a Bunsen burner flame until it ignites, ensuring it has enough oxygen to react.

  2. Oxidation Reaction: As magnesium burns, it reacts with oxygen in the air, forming magnesium oxide (MgO).

  3. Chemical Change: In this reaction, each magnesium atom donates its two outer shell electrons to an oxygen atom, which accepts the electrons to complete its outer shell.

  4. Ionic Compound Formation: The resulting magnesium ions (Mg²⁺) and oxide ions (O²⁻) attract each other to form magnesium oxide, an ionic compound. This process can be summarized as:

    • Magnesium: 2 electrons lost → Mg²⁺
    • Oxygen: 2 electrons gained → O²⁻
  5. Visual Observation: The reaction produces a bright white flame and results in a white powder, which is solid magnesium oxide.

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