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3. (a) Transition metals and group 1 metals have many properties in common because they are all metals - Edexcel - GCSE Chemistry - Question 3 - 2019 - Paper 1

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3. (a) Transition metals and group 1 metals have many properties in common because they are all metals. However some properties of transition metals are different f... show full transcript

Worked Solution & Example Answer:3. (a) Transition metals and group 1 metals have many properties in common because they are all metals - Edexcel - GCSE Chemistry - Question 3 - 2019 - Paper 1

Step 1

Which is a property of transition metals but not of group 1 metals?

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Answer

The correct answer is B: high melting point. Transition metals typically have higher melting points compared to group 1 metals, which have lower melting points due to their metallic bonding.

Step 2

Describe two changes you would see during this reaction.

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Answer

  1. The magnesium metal will gradually dissolve, and you would observe the disappearance of the magnesium ribbon in the solution.
  2. The color of the solution will change from colorless to blue as copper ions are formed and copper metal precipitates from the solution.

Step 3

Give the name of the other substance needed for iron to rust.

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Answer

The other substance needed for iron to rust is oxygen.

Step 4

Describe a simple experiment to compare how much an iron nail rusts in sea water compared to water.

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Answer

  1. Clean two iron nails to ensure there is no pre-existing rust.
  2. Place one nail in a test tube filled with freshwater and the other in a test tube filled with seawater.
  3. Leave both test tubes for a period of time, such as one week.
  4. Observe the nails and record any changes, comparing the rusting and appearance of both nails.

Step 5

Calculate the mass of zinc required to coat the surface of the bucket with a layer of zinc of 200 g m².

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Answer

To calculate the mass of zinc required, use the formula:

extMass=extSurfaceAreaimesextZinclayerthickness ext{Mass} = ext{Surface Area} imes ext{Zinc layer thickness}

Substituting in the values:

extMass=0.68extm2imes200extgm2=136extg ext{Mass} = 0.68 ext{ m}^2 imes 200 ext{ g m}^-2 = 136 ext{ g}

Thus, the mass of zinc required is 136 g.

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