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The ions in sodium chloride solution are sodium ions, Na⁺ chloride ions, Cl⁻ hydrogen ions, H⁺ hydroxide ions, OH⁻ Sodium chloride solution is electrolysed using a direct electric current - Edexcel - GCSE Chemistry - Question 1 - 2013 - Paper 1

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The ions in sodium chloride solution are sodium ions, Na⁺ chloride ions, Cl⁻ hydrogen ions, H⁺ hydroxide ions, OH⁻ Sodium chloride solution is electrolyse... show full transcript

Worked Solution & Example Answer:The ions in sodium chloride solution are sodium ions, Na⁺ chloride ions, Cl⁻ hydrogen ions, H⁺ hydroxide ions, OH⁻ Sodium chloride solution is electrolysed using a direct electric current - Edexcel - GCSE Chemistry - Question 1 - 2013 - Paper 1

Step 1

Which of these ions will be attracted to the cathode during the electrolysis of sodium chloride solution?

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Answer

The ions attracted to the cathode are B) H⁺ and Na⁺ ions. The positively charged hydrogen ions migrate towards the cathode where they can gain electrons.

Step 2

Explain how the half-equation shows that chloride ions are oxidised.

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Answer

In the half-equation 2Cl⁻ → Cl₂ + 2e⁻, chloride ions (Cl⁻) lose electrons during the reaction. This loss of electrons indicates that the chloride ions are being oxidised, as oxidation is defined as the process of losing electrons.

Step 3

Suggest why the solution remaining at the end of the electrolysis is alkaline.

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Answer

The solution becomes alkaline due to the formation of hydroxide ions (OH⁻) during the electrolysis process. These hydroxide ions increase the pH of the solution.

Step 4

State what change you would make to the electrolyte to obtain metallic sodium.

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Answer

To produce metallic sodium, the electrolyte would need to be changed to a molten state, allowing the sodium ions to move freely and be reduced at the cathode.

Step 5

Explain how the oxygen is formed from ions in the solution.

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Answer

When copper sulfate solution is electrolysed, water molecules are oxidised at the anode. The half-equation for this reaction is 2H₂O → O₂ + 4H⁺ + 4e⁻, which shows that oxygen gas is released, while hydrogen ions are produced.

Step 6

Calculate the number of moles of copper, Cu, produced in this experiment.

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Answer

To calculate the number of moles of copper produced, we use the formula:

extMoles=massrelative atomic mass ext{Moles} = \frac{\text{mass}}{\text{relative atomic mass}}

Plugging in the values:

Moles=1.2763.50.02\text{Moles} = \frac{1.27}{63.5} \approx 0.02

Thus, the number of moles of copper produced is approximately 0.02.

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