Photo AI

5. Fluorine, chlorine, bromine and iodine are elements in group 7 of the periodic table - Edexcel - GCSE Chemistry - Question 5 - 2021 - Paper 1

Question icon

Question 5

5.-Fluorine,-chlorine,-bromine-and-iodine-are-elements-in-group-7-of-the-periodic-table-Edexcel-GCSE Chemistry-Question 5-2021-Paper 1.png

5. Fluorine, chlorine, bromine and iodine are elements in group 7 of the periodic table. (a) (i) State the name given to the group 7 elements. (ii) Name one other ... show full transcript

Worked Solution & Example Answer:5. Fluorine, chlorine, bromine and iodine are elements in group 7 of the periodic table - Edexcel - GCSE Chemistry - Question 5 - 2021 - Paper 1

Step 1

State the name given to the group 7 elements.

96%

114 rated

Answer

The name given to the Group 7 elements is halogens.

Step 2

Name one other element that is in group 7.

99%

104 rated

Answer

One other element that is in Group 7 is astatine.

Step 3

Which element is liquid at room temperature and pressure?

96%

101 rated

Answer

The element that is liquid at room temperature and pressure is C. bromine.

Step 4

Which element is dark-grey in colour at room temperature and pressure?

98%

120 rated

Answer

The element that is dark-grey in colour at room temperature and pressure is D. iodine.

Step 5

Calculate the empirical formula of this tin chloride.

97%

117 rated

Answer

To calculate the empirical formula:

  1. Convert grams to moles:

    • Moles of tin (Sn):

    moles of Sn=1.199 g119.0 g/mol0.01008 moles\text{moles of Sn} = \frac{1.199\text{ g}}{119.0\text{ g/mol}} \approx 0.01008 \text{ moles}

    • Moles of chlorine (Cl):

    moles of Cl=1.429 g35.5 g/mol0.04024 moles\text{moles of Cl} = \frac{1.429\text{ g}}{35.5\text{ g/mol}} \approx 0.04024 \text{ moles}

  2. Find the smallest mole ratio:

    • Divide both by the smallest number of moles:

    ratio of Sn=0.010080.01008=1\text{ratio of Sn} = \frac{0.01008}{0.01008} = 1 ratio of Cl=0.040240.010084\text{ratio of Cl} = \frac{0.04024}{0.01008} \approx 4

  3. Empirical formula: Based on the ratio, the empirical formula is SnCl₄.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;