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9 (a) Calcium carbonate reacts with dilute hydrochloric acid to produce carbon dioxide gas - Edexcel - GCSE Chemistry - Question 9 - 2020 - Paper 1

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9 (a) Calcium carbonate reacts with dilute hydrochloric acid to produce carbon dioxide gas. (i) The investigation was carried out with different sized calcium carbo... show full transcript

Worked Solution & Example Answer:9 (a) Calcium carbonate reacts with dilute hydrochloric acid to produce carbon dioxide gas - Edexcel - GCSE Chemistry - Question 9 - 2020 - Paper 1

Step 1

State, using the information in Figure 15, the effect of the surface area of the calcium carbonate on the rate of this reaction.

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Answer

The reaction rate increases with a larger surface area of calcium carbonate. This is evident from the results shown in Figure 15, where the powdered calcium carbonate produces a greater volume of carbon dioxide compared to larger pieces. Therefore, smaller particles provide more surface area for reaction, leading to a higher rate of reaction.

Step 2

Calculate the average rate of reaction in cm³s⁻¹.

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Answer

To calculate the average rate of reaction, we can use the formula:

extrate=volume of gas producedtime taken ext{rate} = \frac{\text{volume of gas produced}}{\text{time taken}}

We know that 90 cm³ of carbon dioxide was produced in 5 minutes. First, we convert 5 minutes to seconds:

5 minutes=5×60=300 seconds5 \text{ minutes} = 5 \times 60 = 300 \text{ seconds}

Now applying the values into the rate formula:

rate=90 cm3300 s=0.3 cm3s1\text{rate} = \frac{90 \text{ cm}^3}{300 \text{ s}} = 0.3 \text{ cm}^3s^{-1}

Step 3

Explain, in terms of particles, why the rate of reaction increased when the temperature was increased.

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Answer

When the temperature increases, the particles gain more energy. This results in:

  1. Higher Energy: Particles have more kinetic energy which causes them to move faster.
  2. More Frequent Collisions: The increased speed leads to more collisions between the acid and calcium carbonate particles.
  3. Successful Collisions: A higher proportion of these collisions have enough energy to overcome the activation energy barrier, increasing the overall rate of reaction.

Step 4

Devise a plan, including the apparatus you would use, to test the student’s prediction.

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Answer

To test the student's prediction about the effect of increasing the concentration of hydrochloric acid on the rate of reaction with zinc, follow this plan:

  1. Apparatus Required:

    • Balance
    • Measuring cylinder or pipette
    • Suitable reaction vessel (e.g., conical flask)
    • Stopwatch or timer
    • Delivery tube
    • Inverted measuring cylinder or gas syringe
    • Thermometer
  2. Method:

    • Measure equal masses of zinc using the balance.
    • Prepare two bottles of dilute hydrochloric acid, one being double the concentration of the other.
    • Pour equal volumes of acid into two reaction vessels.
    • Record the initial temperature of the acid.
    • Add a piece of zinc to one of the vessels immediately after measuring the acid.
    • Start the timer when zinc is added, and place the delivery tube in the inverted measuring cylinder or gas syringe to collect the gas produced.
    • Measure the volume of hydrogen gas produced at intervals until the reaction ceases.
    • Record the final temperatures after the reaction has completed.
    • Repeat the procedure for the second concentration of hydrochloric acid maintaining other factors constant.
    • Analyze the gas volumes produced to compare the rates of reaction.

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