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5. (a) The diagram shows the structure of diamond - Edexcel - GCSE Chemistry - Question 5 - 2014 - Paper 1

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5. (a) The diagram shows the structure of diamond. (i) Describe what each ● represents. (ii) State the type of bonding in the diamond structure. (b) Give the nam... show full transcript

Worked Solution & Example Answer:5. (a) The diagram shows the structure of diamond - Edexcel - GCSE Chemistry - Question 5 - 2014 - Paper 1

Step 1

Describe what each ● represents.

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Answer

Each ● in the structure of diamond represents a carbon atom. In diamond, each carbon atom is tetrahedrally bonded to four other carbon atoms, forming a strong three-dimensional lattice.

Step 2

State the type of bonding in the diamond structure.

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Answer

The type of bonding in the diamond structure is covalent bonding.

Step 3

Give the name of the process used to obtain oxygen from liquid air.

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Answer

The name of the process used to obtain oxygen from liquid air is fractional distillation.

Step 4

What is the Rf value of this dye?

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Answer

The Rf value is calculated using the formula:

Rf=distance moved by dyedistance moved by solventRf = \frac{\text{distance moved by dye}}{\text{distance moved by solvent}}

For this question, the dye moved 2 cm and the solvent moved 8 cm:

Rf=28=0.25Rf = \frac{2}{8} = 0.25

Thus, the correct answer is A 0.25.

Step 5

Describe how the reaction can be carried out, including an explanation of what happens to the magnesium and oxygen atoms when they form magnesium oxide.

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Answer

To carry out the reaction of magnesium with oxygen:

  1. Ignite the Magnesium: Place a strip of magnesium ribbon in a Bunsen burner flame to ignite it.

  2. Reaction with Oxygen: As the magnesium burns, it reacts with oxygen in the air. The equation for the reaction is:

    2Mg+O22MgO2Mg + O_2 \rightarrow 2MgO

  3. Observation: The magnesium burns with a bright white flame, producing a white powder, magnesium oxide (MgO).

  4. Bonding Explanation: Each magnesium atom has 2 electrons in its outer shell, and oxygen has 6. During the reaction, magnesium donates its two electrons to oxygen, which forms a negative ion (O²⁻).

  5. Formation of Ionic Compound: This electron transfer leads to the formation of ionic bonds where magnesium (Mg²⁺) ion is attracted to oxygen (O²⁻), resulting in the formation of magnesium oxide.

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