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5. Fluorine, chlorine, bromine and iodine are elements in group 7 of the periodic table - Edexcel - GCSE Chemistry - Question 5 - 2021 - Paper 1

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5. Fluorine, chlorine, bromine and iodine are elements in group 7 of the periodic table. (a) (i) State the name given to the group 7 elements. (ii) Name one other ... show full transcript

Worked Solution & Example Answer:5. Fluorine, chlorine, bromine and iodine are elements in group 7 of the periodic table - Edexcel - GCSE Chemistry - Question 5 - 2021 - Paper 1

Step 1

State the name given to the group 7 elements.

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Answer

The group 7 elements are commonly known as the halogens.

Step 2

Name one other element that is in group 7.

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Answer

Another element that is in group 7 is astatine.

Step 3

Which element is liquid at room temperature and pressure?

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Answer

The element that is liquid at room temperature and pressure is C. bromine.

Step 4

Which element is dark-grey in colour at room temperature and pressure?

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Answer

The element that is dark-grey in colour at room temperature and pressure is D. iodine.

Step 5

Calculate the empirical formula of this tin chloride.

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Answer

To calculate the empirical formula of tin chloride, follow these steps:

  1. Calculate the moles of tin (Sn):

    Moles of Sn=mass of Snatomic mass of Sn=1.199 g119.0 g/mol0.0101 mol\text{Moles of Sn} = \frac{\text{mass of Sn}}{\text{atomic mass of Sn}} = \frac{1.199 \text{ g}}{119.0 \text{ g/mol}} \approx 0.0101 \text{ mol}

  2. Calculate the moles of chlorine (Cl):

    Moles of Cl=mass of Clatomic mass of Cl=1.429 g35.5 g/mol0.0403 mol\text{Moles of Cl} = \frac{\text{mass of Cl}}{\text{atomic mass of Cl}} = \frac{1.429 \text{ g}}{35.5 \text{ g/mol}} \approx 0.0403 \text{ mol}

  3. Determine the simplest mole ratio:

    • Divide both moles by the smallest number of moles:
    • Sn: 0.01010.0101=1\frac{0.0101}{0.0101} = 1
    • Cl: 0.04030.01014\frac{0.0403}{0.0101} \approx 4
  4. Write the empirical formula:

    The empirical formula is SnCl₄.

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