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Most of the fuels used today are obtained from crude oil - Edexcel - GCSE Chemistry - Question 8 - 2019 - Paper 1

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Most of the fuels used today are obtained from crude oil. (a) Which statement about crude oil is correct? A crude oil is a compound of different hydrocarbons ... show full transcript

Worked Solution & Example Answer:Most of the fuels used today are obtained from crude oil - Edexcel - GCSE Chemistry - Question 8 - 2019 - Paper 1

Step 1

Which statement about crude oil is correct?

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Answer

The correct statement is B: crude oil is a mixture of hydrocarbons. This means that it consists of various hydrocarbons combined together, rather than being a single compound (A), containing only hydrocarbons of the same molecular formula (C), or an unlimited resource (D).

Step 2

State a use for kerosene.

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Answer

Kerosene is commonly used as fuel for aircraft, jets, lamps, and heating.

Step 3

State a use for diesel oil.

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Answer

Diesel oil is typically used in trucks, buses, and generators.

Step 4

State how this property for kerosene compares with the property for diesel oil.

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Answer

One property to compare could be the boiling point. Kerosene has a lower boiling point than diesel oil, which allows it to vaporize more easily and makes it suitable for applications like aviation fuel.

Step 5

Explain, using these formulae, why butane and pentane are neighbouring members of the same homologous series.

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Answer

Butane (C4H10) and pentane (C5H12) are neighbouring members because they differ by a CH2 unit. This consistent difference defines them as part of the same homologous series, where each consecutive member has one additional carbon atom.

Step 6

Calculate the mass of carbon in 100 g of butane.

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The molecular formula of butane is C4H10. The relative molecular mass is 58.0. The mass of carbon in 1 mole of butane (4 carbons) is 4 x 12.0 = 48.0 g. To find the mass of carbon in 100 g of butane:

  1. Calculate the number of moles in 100 g:

    = 1.72 ext{ moles} $$
  2. Calculate the mass of carbon:

    extMassofcarbon=1.72extmolesimes48.0extg/mol=82.56extg ext{Mass of carbon} = 1.72 ext{ moles} imes 48.0 ext{ g/mol} = 82.56 ext{ g}

Thus, the mass of carbon in 100 g of butane is 82.6 g (to three significant figures).

Step 7

Write the word equation for this reaction.

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Answer

The word equation for the combustion of butane is:

Butane + Oxygen → Carbon Dioxide + Water

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