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2 (a) The formula of an aluminium ion is Al$^{3+}$ - Edexcel - GCSE Chemistry - Question 2 - 2017 - Paper 1

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2 (a) The formula of an aluminium ion is Al$^{3+}$. The formula of a sulfate ion is SO$_4^{2-}$. (i) Which of the following is the correct formula of aluminium ... show full transcript

Worked Solution & Example Answer:2 (a) The formula of an aluminium ion is Al$^{3+}$ - Edexcel - GCSE Chemistry - Question 2 - 2017 - Paper 1

Step 1

Which of the following is the correct formula of aluminium sulfate?

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Answer

The correct formula for aluminium sulfate is B Al2_2(SO4_4)3_3. This formula indicates that two aluminium ions combine with three sulfate ions.

Step 2

Give the names of the two solutions that are added.

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Answer

To test for sulfate ions, the two solutions that are typically added are:

  1. Barium chloride (BaCl2_2) - it reacts with sulfate ions to produce barium sulfate, which is a white precipitate.
  2. Hydrochloric acid (HCl) - it helps to provide an acidic environment and ensures the precipitation of barium sulfate.

Step 3

Which of these substances is insoluble in water?

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Answer

The substance that is insoluble in water is C lead sulfate. Lead sulfate does not dissolve well in water compared to the other options.

Step 4

Describe how calcium and oxygen atoms react to form calcium and oxide ions.

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Answer

Calcium (Ca) has the electronic configuration of 2.8.8, meaning it has two electrons in its outer shell. To achieve a stable electronic configuration, calcium loses these two electrons and forms a Ca2+^{2+} ion. Oxygen (O), with an electronic configuration of 2.6, has six electrons in its outer shell. It gains two electrons to complete its outer shell and forms an O2^{2-} ion.

In the reaction, the transfer of electrons occurs:

  • Calcium loses 2 electrons:
ightarrow ext{Ca}^{2+} + 2e^-$$ - Oxygen gains 2 electrons: $$ ext{O} + 2e^- ightarrow ext{O}^{2-}$$ Thus, calcium forms a cation and oxygen forms an anion, resulting in the formation of the ionic compound calcium oxide (CaO). Diagrams can further illustrate the electron transfer and the formation of ions.

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