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A student carried out a flame test on a sample of solid potassium chloride - Edexcel - GCSE Chemistry - Question 10 - 2023 - Paper 2

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A student carried out a flame test on a sample of solid potassium chloride. The student followed this method. step 1 dip a dry wooden splint into water step 2 then ... show full transcript

Worked Solution & Example Answer:A student carried out a flame test on a sample of solid potassium chloride - Edexcel - GCSE Chemistry - Question 10 - 2023 - Paper 2

Step 1

improvement

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Answer

The student could improve their method by ensuring that the wooden splint is clean and uncontaminated before dipping it into the potassium chloride sample. This prevents any cross-contamination from previously used substances that might influence the flame color.

Step 2

reason

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Answer

A clean wooden splint would provide accurate observations, as it would only allow reactions from the potassium chloride sample and not from residual impurities.

Step 3

What colour should the student have seen in the flame if the test had been carried out correctly?

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Answer

The student should have seen a lilac color in the flame if the test was conducted correctly, indicating the presence of potassium ions.

Step 4

Describe the test for chloride ions.

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Answer

To test for chloride ions, dilute nitric acid is added to the sample, followed by a few drops of silver nitrate solution. A white precipitate of silver chloride will form if chloride ions are present.

Step 5

Calculate the mass of barium chloride that must be dissolved in water to make 25 cm³ of solution of this concentration.

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Answer

To find the mass of barium chloride needed, we can use the formula:

extmass=extconcentrationimesextvolume ext{mass} = ext{concentration} imes ext{volume}

Here: Concentration = 83 g/dm³ and Volume = 25 cm³ (which is 0.025 dm³).

Thus,

extmass=83imes0.025=2.075extg ext{mass} = 83 imes 0.025 = 2.075 ext{ g}

Rounded to 2 significant figures, the mass is 2.1 g.

Step 6

Write the ionic equation for this reaction.

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Answer

The ionic equation for the reaction between barium chloride and aluminium sulfate leading to the formation of a precipitate can be written as:

3extBa2+(aq)+3extSO42(aq)+2extAl3+(aq)+6extCl(aq)3extBaSO4(s)+2extAlCl3(aq)3 ext{Ba}^{2+}(aq) + 3 ext{SO}_4^{2-}(aq) + 2 ext{Al}^{3+}(aq) + 6 ext{Cl}^-(aq) \rightarrow 3 ext{BaSO}_4(s) + 2 ext{AlCl}_3(aq)

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