A student carried out a flame test on a sample of solid potassium chloride - Edexcel - GCSE Chemistry - Question 10 - 2023 - Paper 2
Question 10
A student carried out a flame test on a sample of solid potassium chloride.
The student followed this method.
step 1 dip a dry wooden splint into water
step 2 then... show full transcript
Worked Solution & Example Answer:A student carried out a flame test on a sample of solid potassium chloride - Edexcel - GCSE Chemistry - Question 10 - 2023 - Paper 2
Step 1
Explain one improvement that the student could make to their method to obtain a valid conclusion.
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Answer
One improvement that the student could make is to use a clean wooden splint for each test. This would prevent contamination from any previous tests, ensuring that the results are accurate and reflective of the sample being tested.
Step 2
What colour should the student have seen in the flame if the test had been carried out correctly?
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The student should have seen a lilac colour (Option B) in the flame if the test had been carried out correctly, as potassium ions produce this distinctive colour during a flame test.
Step 3
Describe the test for chloride ions.
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To test for chloride ions, a small amount of the sample is dissolved in water to create a solution. Then, a few drops of dilute nitric acid followed by a few drops of silver nitrate solution are added. If chloride ions are present, a white precipitate of silver chloride will form.
Step 4
Calculate the mass of barium chloride that must be dissolved in water to make 25 cm³ of solution of this concentration.
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To find the mass of barium chloride needed, we can use the formula:
Mass = Concentration × Volume.
Firstly, convert the volume from cm³ to dm³:
25 cm³ = 0.025 dm³.
Now, using the concentration of 83 g dm⁻³:
Mass = 83 g dm⁻³ × 0.025 dm³ = 2.075 g.
Rounding to 2 significant figures, the mass of barium chloride required is approximately 2.1 g.
Step 5
Write the ionic equation for this reaction.
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The ionic equation for the reaction between barium chloride and aluminium sulfate is: