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Parents Pricing Home GCSE Edexcel Chemistry Reactions of acids 6 (a) 3.14g of solid copper sulfate was dissolved in water and made up to 250 cm³ of solution
6 (a) 3.14g of solid copper sulfate was dissolved in water and made up to 250 cm³ of solution - Edexcel - GCSE Chemistry - Question 6 - 2022 - Paper 1 Question 6
View full question 6 (a) 3.14g of solid copper sulfate was dissolved in water and made up to 250 cm³ of solution.
Calculate the concentration of this copper sulfate solution in g dm⁻³... show full transcript
View marking scheme Worked Solution & Example Answer:6 (a) 3.14g of solid copper sulfate was dissolved in water and made up to 250 cm³ of solution - Edexcel - GCSE Chemistry - Question 6 - 2022 - Paper 1
Calculate the concentration of this copper sulfate solution in g dm⁻³. Only available for registered users.
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To calculate the concentration, we use the formula:
e x t c o n c e n t r a t i o n ( g d m − 3 e x t ) = e x t m a s s o f s o l i d ( g ) e x t v o l u m e o f s o l u t i o n ( d m 3 e x t ) ext{concentration (g dm}^{-3} ext{)} = \frac{ ext{mass of solid (g)}}{ ext{volume of solution (dm}^{3} ext{)}} e x t co n ce n t r a t i o n ( g d m − 3 e x t ) = e x t v o l u m eo f so l u t i o n ( d m 3 e x t ) e x t ma sso f so l i d ( g ) First, convert the volume from cm³ to dm³:
e x t V o l u m e i n d m 3 = 250 e x t c m 3 1000 = 0.250 e x t d m 3 ext{Volume in dm³} = \frac{250 ext{ cm}^3}{1000} = 0.250 ext{ dm}^3 e x t V o l u m e in d m 3 = 1000 250 e x t c m 3 = 0.250 e x t d m 3
Now, substituting the known values:
e x t c o n c e n t r a t i o n = 3.14 e x t g 0.250 e x t d m 3 = 12.56 e x t g d m − 3 ext{concentration} = \frac{3.14 ext{ g}}{0.250 ext{ dm}^3} = 12.56 ext{ g dm}^{-3} e x t co n ce n t r a t i o n = 0.250 e x t d m 3 3.14 e x t g = 12.56 e x t g d m − 3
State what would be seen in the reaction. Only available for registered users.
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In the reaction, a blue precipitate of copper hydroxide will be observed.
Complete the balanced equation for the reaction by adding a number in front of NaOH. Only available for registered users.
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The balanced equation is:
2 e x t N a O H + e x t C u S O 4 → e x t C u ( O H ) 2 + e x t N a 2 e x t S O 4 2 ext{NaOH} + ext{CuSO}_4 → ext{Cu(OH)}_2 + ext{Na}_2 ext{SO}_4 2 e x t N a O H + e x t C u SO 4 → e x t C u ( O H ) 2 + e x t N a 2 e x t SO 4
Describe how to obtain a pure, dry sample of the precipitate of copper hydroxide from the reaction mixture. Only available for registered users.
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To obtain a pure, dry sample of copper hydroxide precipitate:
Filtration : Pour the reaction mixture through filter paper to separate the solid copper hydroxide precipitate from the liquid.Washing : Rinse the precipitate with distilled water to remove any impurities and excess soluble sodium sulfate.Drying : Transfer the precipitate to a warm place or use a drying oven to remove any remaining moisture, yielding a pure sample of copper hydroxide. Join the GCSE students using SimpleStudy...97% of StudentsReport Improved Results
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