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A student used the apparatus in Figure 3 to investigate the rate of the reaction between a metal and dilute hydrochloric acid - Edexcel - GCSE Chemistry - Question 2 - 2022 - Paper 1

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A student used the apparatus in Figure 3 to investigate the rate of the reaction between a metal and dilute hydrochloric acid. Pieces of the metal were placed in d... show full transcript

Worked Solution & Example Answer:A student used the apparatus in Figure 3 to investigate the rate of the reaction between a metal and dilute hydrochloric acid - Edexcel - GCSE Chemistry - Question 2 - 2022 - Paper 1

Step 1

Identify the measuring device used in the experiment.

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Answer

The experiment utilized a 100 cm³ measuring cylinder to collect the gas produced during the reaction.

Step 2

Calculate the rate of hydrogen production.

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Answer

To determine the rate at which hydrogen gas was produced during the reaction, we first find the volume of hydrogen collected at a specific time and then divide it by that time.

Using the data extracted from the graph, the total volume of hydrogen after 9 minutes is approximately 65 cm³. Therefore, the rate can be calculated as:

extRate=VolumeTime=65 cm39 min7.22 cm3/ min. ext{Rate} = \frac{\text{Volume}}{\text{Time}} = \frac{65 \text{ cm}^3}{9 \text{ min}} \approx 7.22 \text{ cm}^3 \text{/ min}.

Step 3

Explain the trend observed in the graph.

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Answer

The graph indicates that the volume of hydrogen produced increases over time, but the rate of production decreases as the reaction progresses. This occurs because as the reactants are consumed, the collisions between the reactant particles become less frequent, leading to a slower reaction rate.

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