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Calculate the relative atomic mass of titanium in this sample - Edexcel - GCSE Chemistry - Question 6 - 2020 - Paper 1

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Calculate the relative atomic mass of titanium in this sample. Describe how the equipment shown in Figure 7 could be used to find the mass of oxygen that combines w... show full transcript

Worked Solution & Example Answer:Calculate the relative atomic mass of titanium in this sample - Edexcel - GCSE Chemistry - Question 6 - 2020 - Paper 1

Step 1

Calculate the relative atomic mass of titanium

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Answer

To calculate the relative atomic mass of titanium, we need to consider the percentages and masses of the isotopes:

  1. Titanium has the following isotopes and masses:

    • Ti-46: 8%
    • Ti-47: 7.5%
    • Ti-48: 75%
    • Ti-49: 6%
    • Ti-50: 4%
  2. Convert these percentages to masses by multiplying by the atomic mass of titanium isotopes:

    • Total mass = (8 * 46) + (7.5 * 47) + (75 * 48) + (6 * 49) + (4 * 50)
    • Calculate:

    extTotalmass=368+352.5+3600+294+200=4791 ext{Total mass} = 368 + 352.5 + 3600 + 294 + 200 = 4791

  3. Divide the total mass by 100 to obtain the relative atomic mass:

    extRelativeatomicmass=4791100=47.91 ext{Relative atomic mass} = \frac{4791}{100} = 47.91

So, the relative atomic mass of titanium in this sample is approximately 47.91.

Step 2

Describe how the equipment shown in Figure 7 could be used

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Answer

To find the mass of oxygen that combines with 0.500 g of iron wool:

  1. Weigh the empty crucible and its lid to get their initial mass.
  2. Add the 0.500 g of iron wool to the crucible and weigh it again to get the combined mass of iron and crucible.
  3. Heat the crucible gently to allow the iron to react with oxygen in the air, ensuring the lid is loosely placed to allow oxygen to enter.
  4. Once the reaction is complete, allow the crucible to cool down.
  5. Weigh the crucible with the iron oxide formed. Subtract the initial mass of the crucible to find the mass of iron oxide.
  6. The difference in mass reflects the mass of oxygen that combined with the iron.

Step 3

Determine the formula of this oxide of iron

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Answer

Given:

  • Mass of iron = 2.24 g
  • Mass of oxygen = 0.96 g
  • Atomic mass of Fe = 56.0 g/mol
  • Atomic mass of O = 16.0 g/mol
  1. Calculate the number of moles of iron and oxygen:

    • Moles of Fe = \frac{2.24 ext{ g}}{56.0 ext{ g/mol}} = 0.04 ext{ mol}
    • Moles of O = \frac{0.96 ext{ g}}{16.0 ext{ g/mol}} = 0.06 ext{ mol}
  2. Find the simplest mole ratio:

    • Ratio of Fe:O is:
    • Fe : O = 0.04 : 0.06 = 1 : 1.5 = 2 : 3
  3. Therefore, the formula of the oxide of iron is:

    Fe2O3Fe_2O_3

  4. Balanced equation for the reaction is:

    4Fe+3O22Fe2O34Fe + 3O_2 \rightarrow 2Fe_2O_3

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