Copper chloride solution reacts with potassium hydroxide solution to form a precipitate of copper hydroxide and potassium chloride in solution - Edexcel - GCSE Chemistry - Question 4 - 2018 - Paper 1
Question 4
Copper chloride solution reacts with potassium hydroxide solution to form a precipitate of copper hydroxide and potassium chloride in solution.
(a) Balance the equa... show full transcript
Worked Solution & Example Answer:Copper chloride solution reacts with potassium hydroxide solution to form a precipitate of copper hydroxide and potassium chloride in solution - Edexcel - GCSE Chemistry - Question 4 - 2018 - Paper 1
Step 1
Balance the equation for the reaction by putting numbers in the spaces provided.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The balanced equation for the reaction is:
extCuCl2+2extKOHightarrowextCu(OH)2+2extKCl
This shows that two moles of potassium hydroxide react with one mole of copper(II) chloride to produce one mole of copper(II) hydroxide and two moles of potassium chloride.
Step 2
Which of the following is the relative formula mass of copper hydroxide, Cu(OH)₂?
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To calculate the relative formula mass of copper hydroxide, Cu(OH)₂:
Atomic mass of Cu = 63.5
Atomic mass of O = 16
Atomic mass of H = 1
Thus, the relative formula mass is:
63.5+2(16)+2(1)=63.5+32+2=97.5
The correct answer is C 97.5.
Step 3
Calculate the percentage by mass of potassium in potassium chloride.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To find the percentage by mass of potassium in potassium chloride (KCl):
Relative atomic mass of K = 39
Relative atomic mass of Cl = 35.5
Relative formula mass of KCl = 39 + 35.5 = 74.5
Now, the percentage by mass of potassium is calculated as follows:
ext{Percentage by mass of K} = rac{ ext{Mass of K}}{ ext{Mass of KCl}} imes 100 = rac{39}{74.5} imes 100 \\ ext{Percentage by mass of K} \\ = 52.23\% \\ ext{(approximately)}