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Copper chloride solution reacts with potassium hydroxide solution to form a precipitate of copper hydroxide and potassium chloride in solution - Edexcel - GCSE Chemistry - Question 4 - 2018 - Paper 1

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Copper chloride solution reacts with potassium hydroxide solution to form a precipitate of copper hydroxide and potassium chloride in solution. (a) Balance the equa... show full transcript

Worked Solution & Example Answer:Copper chloride solution reacts with potassium hydroxide solution to form a precipitate of copper hydroxide and potassium chloride in solution - Edexcel - GCSE Chemistry - Question 4 - 2018 - Paper 1

Step 1

Balance the equation for the reaction by putting numbers in the spaces provided.

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Answer

The balanced equation for the reaction is:

extCuCl2+2extKOHightarrowextCu(OH)2+2extKCl ext{CuCl}_2 + 2 ext{KOH} ightarrow ext{Cu(OH)}_2 + 2 ext{KCl}

This shows that two moles of potassium hydroxide react with one mole of copper(II) chloride to produce one mole of copper(II) hydroxide and two moles of potassium chloride.

Step 2

Which of the following is the relative formula mass of copper hydroxide, Cu(OH)₂?

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Answer

To calculate the relative formula mass of copper hydroxide, Cu(OH)₂:

  1. Atomic mass of Cu = 63.5
  2. Atomic mass of O = 16
  3. Atomic mass of H = 1

Thus, the relative formula mass is:

63.5+2(16)+2(1)=63.5+32+2=97.563.5 + 2(16) + 2(1) = 63.5 + 32 + 2 = 97.5

The correct answer is C 97.5.

Step 3

Calculate the percentage by mass of potassium in potassium chloride.

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Answer

To find the percentage by mass of potassium in potassium chloride (KCl):

  1. Relative atomic mass of K = 39
  2. Relative atomic mass of Cl = 35.5
  3. Relative formula mass of KCl = 39 + 35.5 = 74.5

Now, the percentage by mass of potassium is calculated as follows:

ext{Percentage by mass of K} = rac{ ext{Mass of K}}{ ext{Mass of KCl}} imes 100 = rac{39}{74.5} imes 100 \\ ext{Percentage by mass of K} \\ = 52.23\% \\ ext{(approximately)}

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