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Question 6
Gases and ammonia (a) Hydrogen reacts with oxygen to form water vapour. $$2H_2(g) + O_2(g) → 2H_2O(g)$$ If 200 cm³ of hydrogen react completely with 100 cm³ of ox... show full transcript
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First, we need to determine how many moles of zinc are in 13.0 g. The molar mass of zinc (Zn) is 65.0 g/mol.
Number of moles of zinc = ( \frac{13.0 \text{ g}}{65.0 \text{ g/mol}} = 0.2 \text{ moles} )
According to the equation, 1 mole of zinc produces 1 mole of hydrogen gas. Therefore, 0.2 moles of zinc will produce 0.2 moles of hydrogen gas.
Next, to find the volume of hydrogen gas produced, we use the fact that 1 mole of gas occupies 24 dm³ at room temperature and pressure.
Volume of hydrogen = ( 0.2 \text{ moles} \times 24 \text{ dm}^3 = 4.8 \text{ dm}^3 )
Thus, the maximum volume of hydrogen formed is 4.8 dm³.
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