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10 (a) Nitric acid can be titrated with a solution of ammonia - Edexcel - GCSE Chemistry - Question 10 - 2019 - Paper 1
Question 10
10 (a) Nitric acid can be titrated with a solution of ammonia. (i) State the type of reaction occurring when nitric acid reacts with ammonia. (ii) What salt is fo... show full transcript
Worked Solution & Example Answer:10 (a) Nitric acid can be titrated with a solution of ammonia - Edexcel - GCSE Chemistry - Question 10 - 2019 - Paper 1
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(b) Calculate the minimum volume of air, measured at room temperature and pressure, required to react with 1000 g nitrogen oxide to form nitrogen dioxide.
Answer
To find the minimum volume of air required to react with 1000 g of nitrogen oxide (NO), we first calculate the number of moles of NO present:
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Calculate the molar mass of nitrogen oxide (NO):
ext{Molar mass of NO} = 14 ext{ (N)} + 16 ext{ (O)} = 30 ext{ g/mol}
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Determine the number of moles of NO in 1000 g:
ext{Number of moles} = rac{1000 ext{ g}}{30 ext{ g/mol}} = rac{1000}{30} ext{ mol} gtrapprox 33.33 ext{ mol}
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From the balanced equation 2NO + O<sub>2</sub> → 2NO<sub>2</sub>, it is clear that 2 moles of NO require 1 mole of O<sub>2</sub>.
Therefore, the moles of O<sub>2</sub> needed for 33.33 moles of NO is:
ext{Moles of O<sub>2</sub>} = rac{33.33}{2} = 16.67 ext{ mol}
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Since air is approximately 20% oxygen, we can calculate the total moles of air required:
ext{Moles of air} = rac{16.67 ext{ mol}}{0.20} = 83.35 ext{ mol}
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Finally, to convert moles of air to volume at room temperature and pressure (1 mol = 24 dm<sup>3</sup>):
ext{Volume of air} = 83.35 ext{ mol} imes 24 ext{ dm<sup>3</sup>/mol} gtrapprox 2000.4 ext{ dm<sup>3</sup>}
Thus, the minimum volume of air required is approximately 2000.4 dm<sup>3</sup>.