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The diagram shows the structure of a propene molecule - Edexcel - GCSE Chemistry - Question 3 - 2011 - Paper 1

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The diagram shows the structure of a propene molecule. (a) Which row of the table describes propene? Put a cross (✗) in the box next to your answer. | | h... show full transcript

Worked Solution & Example Answer:The diagram shows the structure of a propene molecule - Edexcel - GCSE Chemistry - Question 3 - 2011 - Paper 1

Step 1

Which row of the table describes propene?

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Answer

Propene is an unsaturated hydrocarbon. Therefore, the correct row is D: yes (hydrocarbon) and yes (unsaturated).

Step 2

Draw a diagram to show the part of a poly(propene) molecule formed from two propene molecules.

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Answer

To represent the polymerization of propene, draw two propene monomers:

     H   H         H   H
      \ /           \ / 
       C=C         C=C
      / \           / \
     H   H         H   H

Then, connect the monomers into a polymer:

H   H   H   H   H   H
|\ /|\ /|\ /|\ /|\ /|
C=C C=C C=C C=C C=C C
  |   |   |   |   |
  H   H   H   H   H   H

This diagram shows the part of the poly(propene) molecule formed.

Step 3

Describe a test that shows that molecules of propene contain carbon to carbon double bonds.

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Answer

A typical test to confirm the presence of carbon to carbon double bonds (i.e., alkenes) is the bromine water test. When bromine water (an orange solution) is added to propene, the solution decolorizes, indicating that a reaction occurred, and confirming the presence of double bonds. The bromine adds across the double bond, forming a dibromide compound.

Step 4

This equation shows the cracking of decane to produce propene and butane.

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Answer

To find the total mass of products formed when 17 g of decane is cracked:

  1. Calculate the molar mass of decane (C₁₀H₂₂) = 10(12) + 22(1) = 142 g/mol.
  2. For every 1 mole of decane (142 g), 1 mole of propene (C₃H₆) and 1 mole of butane (C₄H₁₀) are produced.
  3. Calculate the total moles of decane cracked: moles=massmolar mass=171420.1196 extmolesmoles = \frac{mass}{molar \ mass} = \frac{17}{142} ≈ 0.1196 \ ext{moles}
  4. Therefore, total mass of products = moles × (molar mass of propene + molar mass of butane) = 0.1196×(42+58)=0.1196×100=11.96g0.1196 \times (42 + 58) = 0.1196 \times 100 = 11.96 \text{g}

Step 5

Explain what is meant by cracking.

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Answer

Cracking is a chemical process used to break down large hydrocarbon molecules, usually derived from crude oil, into smaller, more useful molecules, such as alkenes and alkanes. This process increases the yield of valuable products like gasoline and chemical feedstocks.

Step 6

Explain why it is necessary to crack crude oil fractions that contain large molecules.

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Answer

Cracking is necessary because large hydrocarbon molecules from crude oil fractions are less valuable; they are typically less efficient as fuels, and have limited uses in the chemical industry. By cracking these large molecules, we can produce smaller, more useful ones, such as alkenes that can serve as monomers for polymer production or are used as fuel for vehicles.

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