Photo AI

Jessica runs for 15 minutes at an average speed of 6 miles per hour - Edexcel - GCSE Maths - Question 7 - 2022 - Paper 3

Question icon

Question 7

Jessica-runs-for-15-minutes-at-an-average-speed-of-6-miles-per-hour-Edexcel-GCSE Maths-Question 7-2022-Paper 3.png

Jessica runs for 15 minutes at an average speed of 6 miles per hour. She then runs for 40 minutes at an average speed of 9 miles per hour. It takes Amy 45 minutes t... show full transcript

Worked Solution & Example Answer:Jessica runs for 15 minutes at an average speed of 6 miles per hour - Edexcel - GCSE Maths - Question 7 - 2022 - Paper 3

Step 1

Calculate the distance for the first part of Jessica's run

96%

114 rated

Answer

To find the distance Jessica runs during the first part of her run, we use the formula:

extDistance=extSpeedimesextTime ext{Distance} = ext{Speed} imes ext{Time}

For the first part:

Speed = 6 miles/hour Time = 15 minutes = \frac{15}{60} \text{ hours} = 0.25 \text{ hours}

Thus,

extDistance=6×0.25=1.5 miles ext{Distance} = 6 \times 0.25 = 1.5 \text{ miles}

Step 2

Calculate the distance for the second part of Jessica's run

99%

104 rated

Answer

For the second part:

Speed = 9 miles/hour Time = 40 minutes = \frac{40}{60} \text{ hours} = \frac{2}{3} \text{ hours}

Thus,

extDistance=9×23=6 miles ext{Distance} = 9 \times \frac{2}{3} = 6 \text{ miles}

Step 3

Calculate total distance run by Jessica

96%

101 rated

Answer

The total distance Jessica runs is the sum of both parts:

extTotalDistance=1.5+6=7.5 miles ext{Total Distance} = 1.5 + 6 = 7.5 \text{ miles}

Step 4

Calculate Amy's average speed

98%

120 rated

Answer

Amy takes 45 minutes to run the same total distance of 7.5 miles:

Time taken by Amy = 45 minutes = \frac{45}{60} \text{ hours} = 0.75 \text{ hours}

Using the average speed formula:

extAverageSpeed=extTotalDistanceextTime=7.50.75=10 miles/hour ext{Average Speed} = \frac{ ext{Total Distance}}{ ext{Time}} = \frac{7.5}{0.75} = 10 \text{ miles/hour}

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;