Using $x_{t} = -2 - \frac{4}{x_{t}}$ with $x_{t} = -2.5$
(a) find the values of $x_{t}$, $x_{1}$, and $x_{2}$ - Edexcel - GCSE Maths - Question 16 - 2017 - Paper 3
Question 16
Using $x_{t} = -2 - \frac{4}{x_{t}}$ with $x_{t} = -2.5$
(a) find the values of $x_{t}$, $x_{1}$, and $x_{2}$.
$x_{1} = $
$x_{2} = $
$x_{3} = $
(b) Explain the ... show full transcript
Worked Solution & Example Answer:Using $x_{t} = -2 - \frac{4}{x_{t}}$ with $x_{t} = -2.5$
(a) find the values of $x_{t}$, $x_{1}$, and $x_{2}$ - Edexcel - GCSE Maths - Question 16 - 2017 - Paper 3
Step 1
Explain the relationship between the values of $x_{1}$, $x_{2}$, and $x_{t}$, and the equation $x^{2} + 2x + 4 = 0$
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Answer
The values of x1, x2, and xt are related through the iterative method of solving the equation. In particular, they represent successive approximations of a solution to the quadratic equation x2+2x+4=0. The equation has complex solutions given that its discriminant (b2−4ac=22−4(1)(4)<0) is negative.
Thus, x1 and subsequent iterations are estimates that converge to one of these complex solutions. The iterative process helps in estimating solutions for nonlinear equations and illustrates how different x values lead back to the original equation.