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For a start to the process, $$ rac{4R}{T} = rac{2d}{dt}\left(\frac{P}{T}\right) = \frac{\frac{R}{2}}{500 / K}$$ For a complete process to find $W_{s}$, $$W_{s} = \frac{540}{3R}$$ Any arrangement equivalent to this equation acceptable. - Edexcel - GCSE Maths - Question 15 - 2022 - Paper 1
Question 15
For a start to the process, $$ rac{4R}{T} = rac{2d}{dt}\left(\frac{P}{T}\right) = \frac{\frac{R}{2}}{500 / K}$$ For a complete process to find $W_{s}$, $$W_{s} =... show full transcript
Worked Solution & Example Answer:For a start to the process, $$ rac{4R}{T} = rac{2d}{dt}\left(\frac{P}{T}\right) = \frac{\frac{R}{2}}{500 / K}$$ For a complete process to find $W_{s}$, $$W_{s} = \frac{540}{3R}$$ Any arrangement equivalent to this equation acceptable. - Edexcel - GCSE Maths - Question 15 - 2022 - Paper 1
Step 1
For a start to the process
Answer
To start, we will set up the equation for the process. Given, rac{4R}{T} = \frac{2d}{dt}\left(\frac{P}{T}\right)
We know that the relationship involves derivatives with respect to temperature. By isolating terms, we can derive expressions related to the system under study.
Step 2