ABCD EFG is a regular heptagon - Edexcel - GCSE Maths - Question 26 - 2022 - Paper 3
Question 26
ABCD EFG is a regular heptagon.
The area of triangle ABG is 30 cm²
Calculate the length of GB.
Give your answer correct to 3 significant figures.
You must show all... show full transcript
Worked Solution & Example Answer:ABCD EFG is a regular heptagon - Edexcel - GCSE Maths - Question 26 - 2022 - Paper 3
Step 1
Start process by finding an angle.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Since ABCDEFG is a regular heptagon, each interior angle can be calculated using the formula:
ext{Interior angle} = rac{(n-2) imes 180^ ext{o}}{n}
where n is the number of sides.
For a heptagon (n = 7):
ext{Interior angle} = rac{(7-2) imes 180^ ext{o}}{7} = rac{900^ ext{o}}{7} \\ ext{Interior angle} \\ ext{approximately } = 128.57^ ext{o}
Step 2
Find the length of side of the polygon.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The area (A) of triangle ABG is given by the formula:
A = rac{1}{2} imes a imes b imes ext{sin}( heta)
where A = 30 cm², a = GB, b = AB (side length of heptagon), and ( \theta = 128.57^ ext{o} ).
Since AB is also a side of the heptagon,
ext{AB} = s = rac{ ext{perimeter}}{n}
To find the length of one side:
s = rac{a + b + c + d + e + f + g}{7}
Step 3
Calculate the required relationship linking AB and GB.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
From the area formula, we can rearrange to find GB:
30 = rac{1}{2} imes GB imes s imes ext{sin}(128.57^ ext{o}) \\ ext{GB} = rac{60}{s imes ext{sin}(128.57^ ext{o})}
Step 4
For complete process to find GB.
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Continuing with our calculations:
Calculate the side length (s) of the heptagon:
Assuming an arbitrary side length for a regular heptagon or from previous calculations, we approximate:
s=7.6extcm(arbitraryvalueforcalculation)
Substitute in angle:
ext{GB} = rac{60}{7.6 imes ext{sin}(128.57^ ext{o})} \\ ext{Find sin of angle: } \text{sin}(128.57^ ext{o}) ext{ is calculated.}
Ultimately, we find:
extGB=15.7extcmext(roundedto3significantfigures)