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The graph of the curve with equation $y = f(x)$ is shown on the grid below - Edexcel - GCSE Maths - Question 21 - 2020 - Paper 2

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The graph of the curve with equation $y = f(x)$ is shown on the grid below. (a) On the grid above, sketch the graph of the curve with equation $y = f(-x)$. The cur... show full transcript

Worked Solution & Example Answer:The graph of the curve with equation $y = f(x)$ is shown on the grid below - Edexcel - GCSE Maths - Question 21 - 2020 - Paper 2

Step 1

On the grid above, sketch the graph of the curve with equation $y = f(-x)$

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Answer

To sketch the graph of y=f(x)y = f(-x), we reflect the graph of y=f(x)y = f(x) across the y-axis. This involves taking each point (x,y)(x, y) on the original graph and transforming it to (x,y)(-x, y).

Thus, the critical points of the original function should be mirrored:

  • The point (0,2)(0, 2) becomes (0,2)(0, 2) (remains unchanged).
  • The point (2,0)(2, 0) becomes (2,0)(-2, 0).
  • The point (4,0)(4, 0) becomes (4,0)(-4, 0).

Following this transformation, sketch the curve ensuring it passes through the newly reflected points.

Step 2

Find an equation for $S$

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Answer

To find the equation for curve SS, we first determine the translation that occurs from curve CC to curve SS. The point (1,6)(1, 6) on curve CC is mapped to (4,6)(4, 6) on curve SS.

The horizontal translation can be calculated as 41=34 - 1 = 3. As there is no change in the y-coordinate, the vertical translation is 00.

Thus, we apply a horizontal shift of 3 units to the left for all x-coordinates in the original equation of curve CC.

The equation for curve CC is: y=5+2xx2y = 5 + 2x - x^2

After applying the translation, substitute xx with (x3)(x - 3) in the equation: y=5+2(x3)(x3)2y = 5 + 2(x - 3) - (x - 3)^2

Expanding this gives: y=5+2x6(x26x+9)y = 5 + 2x - 6 - (x^2 - 6x + 9) y=56+2x+6x9y = 5 - 6 + 2x + 6x - 9 y=8xx210y = 8x - x^2 - 10

Thus, the equation for curve SS is: y=x2+8x10y = -x^2 + 8x - 10

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