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ABCD is a rectangle - Edexcel - GCSE Maths - Question 19 - 2017 - Paper 1

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ABCD is a rectangle. A. E and B are points on the straight line L with equation x + 2y = 12. A and D are points on the straight line M. AE = EB Find an equation f... show full transcript

Worked Solution & Example Answer:ABCD is a rectangle - Edexcel - GCSE Maths - Question 19 - 2017 - Paper 1

Step 1

A. E and B are points on the straight line L with equation x + 2y = 12.

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Answer

To find points E and B on the line L, we can rearrange the equation to express y in terms of x:

2y=12x2y = 12 - x
y=12x+6y = -\frac{1}{2}x + 6

This indicates that the gradient (slope) of line L is -\frac{1}{2}. Hence, line L has points where the y-coordinate can be calculated for various x-values.

Step 2

A and D are points on the straight line M.

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Answer

To find the gradient of line M, we use the condition AE = EB. Given that AD is a vertical line (due to the rectangle), the positions of A and D can be expressed in terms of the coordinates from line L. Hence, the gradient of line M must be perpendicular to line L.

If the slope of line L is -\frac{1}{2}, then the slope (m) of line M is the negative reciprocal, which is 2.

Thus, we can express line M as:

yyA=2(xxA)y - y_A = 2(x - x_A)

Which we can rearrange for a specific equation.

Step 3

Find an equation for M.

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Answer

Substituting a specific point, say A’s coordinates into the equation gives us:

For example, if A = (0, 6) (from line L), this substitution results in:

y6=2(x0)y - 6 = 2(x - 0)

Thus, the equation of line M becomes:

y=2x+6y = 2x + 6

This is the equation of line M based on the conditions given.

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