1. Solve 14n > 11n + 6 (b) On the number line below, show the set of values of x for which −2 < x + 3 ≤ 4. - Edexcel - GCSE Maths - Question 2 - 2019 - Paper 2

First, we need to solve the compound inequality.

Starting with the left side:

$-2 < x + 3$

Subtracting 3 from both sides gives:

$-2 - 3 < x$

which simplifies to:

$-5 < x$

Next, for the right side of the inequality:

$x + 3 ≤ 4$

Again, subtracting 3 from both sides gives:

$x ≤ 4 - 3$

which simplifies to:

$x ≤ 1$

Combining both results, we have:

$-5 < x ≤ 1$

This indicates that on the number line, you should draw an open circle at -5 (not including -5) and a closed circle at 1 (including 1), and shade the region between these two points.