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The cumulative frequency table shows information about the times, in minutes, taken by 40 people to complete a puzzle - Edexcel - GCSE Maths - Question 11 - 2019 - Paper 1

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The cumulative frequency table shows information about the times, in minutes, taken by 40 people to complete a puzzle. Time (m minutes) 20 < m ≤ 40 5 20 < m ≤ 60 ... show full transcript

Worked Solution & Example Answer:The cumulative frequency table shows information about the times, in minutes, taken by 40 people to complete a puzzle - Edexcel - GCSE Maths - Question 11 - 2019 - Paper 1

Step 1

On the grid below, draw a cumulative frequency graph for this information.

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Answer

To construct the cumulative frequency graph, we will plot the cumulative frequency against the upper class boundaries of the corresponding time intervals. The points to plot are:

  • (40, 5)
  • (60, 25)
  • (80, 38)
  • (100, 40)

After plotting these points, connect them with a smooth curve, ensuring to label the graph accurately.

Step 2

Use your graph to find an estimate for the interquartile range.

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Answer

To find the interquartile range, we need to determine the first quartile (Q1) and the third quartile (Q3) from the graph. From the cumulative frequency of 40, calculate:

  • Q1: Locate the point at the 10th percentile (0.25 * 40 = 10) on the vertical axis and trace horizontally to find the corresponding time on the horizontal axis.
  • Q3: Locate the point at the 30th percentile (0.75 * 40 = 30) and do the same. The interquartile range is given by Q3 - Q1.

Step 3

Use your graph to find an estimate for the probability that this person took between 50 minutes and 90 minutes to complete the puzzle.

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Answer

To calculate this probability from the graph, first determine the cumulative frequencies at 50 minutes and 90 minutes by tracing up from these time values to the graph- follow horizontally and back down to read the frequencies. The probability is then calculated as:

P(50<m<90)=C(90)C(50)40P(50 < m < 90) = \frac{C(90) - C(50)}{40} where C(90) and C(50) are the cumulative frequencies corresponding to 90 and 50 minutes, respectively.

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