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The table gives information about the times taken, in seconds, by 18 students to run a race - Edexcel - GCSE Maths - Question 6 - 2019 - Paper 3

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The table gives information about the times taken, in seconds, by 18 students to run a race. | Time (< seconds) | Frequency | | ---------------- | --------- | | 5 <... show full transcript

Worked Solution & Example Answer:The table gives information about the times taken, in seconds, by 18 students to run a race - Edexcel - GCSE Maths - Question 6 - 2019 - Paper 3

Step 1

Calculate midpoint for each time interval

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Answer

To estimate the mean time, we start by calculating the midpoints for each time interval:

  • For the interval 5 < i < 10, the midpoint is ( M_1 = \frac{5 + 10}{2} = 7.5 )
  • For the interval 10 < i < 15, the midpoint is ( M_2 = \frac{10 + 15}{2} = 12.5 )
  • For the interval 15 < i < 20, the midpoint is ( M_3 = \frac{15 + 20}{2} = 17.5 )
  • For the interval 20 < i < 25, the midpoint is ( M_4 = \frac{20 + 25}{2} = 22.5 )

Step 2

Multiply midpoints by their frequencies

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Answer

Next, we multiply each midpoint by its respective frequency:

  • For 5 < i < 10: ( 7.5 \times 1 = 7.5 )
  • For 10 < i < 15: ( 12.5 \times 2 = 25.0 )
  • For 15 < i < 20: ( 17.5 \times 7 = 122.5 )
  • For 20 < i < 25: ( 22.5 \times 8 = 180.0 )

Step 3

Sum the products

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Now we sum the products obtained from the previous step:

( 7.5 + 25.0 + 122.5 + 180.0 = 335.0 )

Step 4

Calculate total frequency

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Next, we calculate the total frequency:

( 1 + 2 + 7 + 8 = 18 )

Step 5

Estimate the mean time

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Finally, we estimate the mean time by dividing the total sum of the products by the total frequency:

[ \text{Mean Time} = \frac{335.0}{18} \approx 18.61 ]

Rounding this to three significant figures gives us:

( 18.6 ) seconds.

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