For methods to find expected number of model B,
$ q = \frac{40000}{e} $
$ n = 15 $
$ E = \frac{15}{q} \times 10000 $
$ = \frac{15}{23.1 + 15 - 30 - 12} \times 10000 $
$ = .. - Edexcel - GCSE Maths - Question 5 - 2022 - Paper 1
Question 5
For methods to find expected number of model B,
$ q = \frac{40000}{e} $
$ n = 15 $
$ E = \frac{15}{q} \times 10000 $
$ = \frac{15}{23.1 + 15 - 30 - 12} \times ... show full transcript
Worked Solution & Example Answer:For methods to find expected number of model B,
$ q = \frac{40000}{e} $
$ n = 15 $
$ E = \frac{15}{q} \times 10000 $
$ = \frac{15}{23.1 + 15 - 30 - 12} \times 10000 $
$ = .. - Edexcel - GCSE Maths - Question 5 - 2022 - Paper 1
Step 1
For methods to find expected number of model B:
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Answer
To find the expected number of model B, we first need to define the required values, especially the variable q which represents the expected number in this context.
Given,
Total value =40000 (likely a total sum of quantities or some cumulative metric)
Equally important, we use a finalized value of 15 as mentioned in our context.
The formula to compute the expected number becomes:
E=q15×10000
Where E is the expected number.
Step 2
$ E = \frac{15}{q} \times 10000 $
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Answer
Substituting the value of q computed:
q=23.1+15−30−12
Using this value in our formula for expected number, we compute:
E=23.1+15−30−1215×10000
Evaluating this provides the expected number of models B.
Step 3
Final Calculation:
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Answer
Upon calculating the above expression, one should arrive at a derived expected value of model B, ensuring to maintain unit consistency throughout the calculations.