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For methods to find expected number of model B, $ q = \frac{40000}{e} $ $ n = 15 $ $ E = \frac{15}{q} \times 10000 $ $ = \frac{15}{23.1 + 15 - 30 - 12} \times 10000 $ $ = .. - Edexcel - GCSE Maths - Question 5 - 2022 - Paper 1

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For-methods-to-find-expected-number-of-model-B,---$-q-=-\frac{40000}{e}-$--$-n-=-15-$--$-E-=-\frac{15}{q}-\times-10000-$---$-=-\frac{15}{23.1-+-15---30---12}-\times-10000-$--$-=-..-Edexcel-GCSE Maths-Question 5-2022-Paper 1.png

For methods to find expected number of model B, $ q = \frac{40000}{e} $ $ n = 15 $ $ E = \frac{15}{q} \times 10000 $ $ = \frac{15}{23.1 + 15 - 30 - 12} \times ... show full transcript

Worked Solution & Example Answer:For methods to find expected number of model B, $ q = \frac{40000}{e} $ $ n = 15 $ $ E = \frac{15}{q} \times 10000 $ $ = \frac{15}{23.1 + 15 - 30 - 12} \times 10000 $ $ = .. - Edexcel - GCSE Maths - Question 5 - 2022 - Paper 1

Step 1

For methods to find expected number of model B:

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Answer

To find the expected number of model B, we first need to define the required values, especially the variable qq which represents the expected number in this context.

Given,

  • Total value =40000= 40000 (likely a total sum of quantities or some cumulative metric)
  • Equally important, we use a finalized value of 15 as mentioned in our context.

The formula to compute the expected number becomes:

E=15q×10000E = \frac{15}{q} \times 10000

Where EE is the expected number.

Step 2

$ E = \frac{15}{q} \times 10000 $

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Answer

Substituting the value of qq computed:

q=23.1+153012q = 23.1 + 15 - 30 - 12

Using this value in our formula for expected number, we compute:

E=1523.1+153012×10000E = \frac{15}{23.1 + 15 - 30 - 12} \times 10000

Evaluating this provides the expected number of models B.

Step 3

Final Calculation:

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Answer

Upon calculating the above expression, one should arrive at a derived expected value of model B, ensuring to maintain unit consistency throughout the calculations.

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