f and g are functions such that f(x) = \frac{2}{x^2} and g(x) = 4x^3 (a) Find f(-5) (b) Find fg(1) - Edexcel - GCSE Maths - Question 12 - 2018 - Paper 2

First, we need to find g(1):

$g(1) = 4(1)^3 = 4 \cdot 1 = 4$

Now, we will substitute g(1) into f:

$f(g(1)) = f(4) = \frac{2}{(4)^2}$

Calculating this, we get:

$f(4) = \frac{2}{16} = \frac{1}{8}$

Therefore, the answer is:

$fg(1) = \frac{1}{8}$