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10 (a) Simplify \[ \frac{x - 1}{5(x - 1)^2} \] (b) Factorise fully \[50 - 2y^2\] - Edexcel - GCSE Maths - Question 11 - 2018 - Paper 1

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10-(a)-Simplify-\[-\frac{x---1}{5(x---1)^2}-\]--(b)-Factorise-fully-\[50---2y^2\]--Edexcel-GCSE Maths-Question 11-2018-Paper 1.png

10 (a) Simplify \[ \frac{x - 1}{5(x - 1)^2} \] (b) Factorise fully \[50 - 2y^2\]

Worked Solution & Example Answer:10 (a) Simplify \[ \frac{x - 1}{5(x - 1)^2} \] (b) Factorise fully \[50 - 2y^2\] - Edexcel - GCSE Maths - Question 11 - 2018 - Paper 1

Step 1

Simplify \[ \frac{x - 1}{5(x - 1)^2} \]

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Answer

To simplify the expression, we can start by factoring out the common term in the numerator and denominator:

[ \frac{x - 1}{5(x - 1)^2} = \frac{1}{5(x - 1)} ]
This leaves us with (\frac{1}{5(x - 1)}), since the ((x - 1)) in the numerator cancels out one of the ((x - 1)) in the denominator.

Step 2

Factorise fully \[50 - 2y^2\]

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Answer

In this expression, we notice that we can factor out a common factor of 2:

[50 - 2y^2 = 2(25 - y^2)]

Next, we observe that (25 - y^2) is a difference of squares, which can be factored further:

[25 - y^2 = (5 - y)(5 + y)]

Putting it all together, we get the fully factored form:

[50 - 2y^2 = 2(5 - y)(5 + y)]

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