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A, B, C and D are points on the circumference of a circle, centre O - Edexcel - GCSE Maths - Question 13 - 2018 - Paper 2

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A, B, C and D are points on the circumference of a circle, centre O. FDE is a tangent to the circle. (a) Show that $y - x = 90$. You must give a reason for each st... show full transcript

Worked Solution & Example Answer:A, B, C and D are points on the circumference of a circle, centre O - Edexcel - GCSE Maths - Question 13 - 2018 - Paper 2

Step 1

Show that $y - x = 90$

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Answer

To show that yx=90y - x = 90, we can reference properties of angles in a circle:

  1. The angle yy is the angle at point DD inscribed in the circle, which subtends arc EFEF.
  2. The angle xx is the angle at point FF which subtends the same arc EFEF, but it lies outside of the circle.
  3. According to the Alternate Segment Theorem, we know that an angle formed by a tangent and a chord through the point of contact is equal to the angle in the alternate segment.

Hence, we can conclude: y=90+xext(usingthepropertyofthetangent)y = 90 + x ext{ (using the property of the tangent)} which means: $$y - x = 90.$

Step 2

Is Dylan correct?

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Answer

Dylan is not correct. The values he proposed are not possible within the context of the circle's angles.

Specifically, since yy must be an angle inside a triangle, it cannot exceed 180 degrees. If y=200y = 200, this violates the triangle condition that any angle must be less than 180 degrees. Therefore, the assertion yx=90y - x = 90 cannot hold true with the values Dylan suggested.

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