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12 (a) Find the value of $81^{ rac{1}{2}}$ - Edexcel - GCSE Maths - Question 12 - 2017 - Paper 1

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12 (a) Find the value of $81^{ rac{1}{2}}$. (b) Find the value of $\left( \frac{64}{125} \right)^{\frac{3}{2}}$.

Worked Solution & Example Answer:12 (a) Find the value of $81^{ rac{1}{2}}$ - Edexcel - GCSE Maths - Question 12 - 2017 - Paper 1

Step 1

Find the value of $81^{\frac{1}{2}}$

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Answer

To find the value of 811281^{\frac{1}{2}}, we recognize that this expression represents the square root of 81. Therefore:

8112=81=9.81^{\frac{1}{2}} = \sqrt{81} = 9.

Thus, the answer is 9.

Step 2

Find the value of $\left( \frac{64}{125} \right)^{\frac{3}{2}}$

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Answer

To evaluate (64125)32\left( \frac{64}{125} \right)^{\frac{3}{2}}, we will first find the square root of both the numerator and the denominator:

(64125)32=(64)3(125)3.\left( \frac{64}{125} \right)^{\frac{3}{2}} = \frac{(\sqrt{64})^3}{(\sqrt{125})^3}.

Now, calculating each square root:

  • 64=8\sqrt{64} = 8, so (64)3=83=512\left( \sqrt{64} \right)^3 = 8^3 = 512.
  • 125=55\sqrt{125} = 5\sqrt{5}, so (125)3=(55)3=12555=6255\left( \sqrt{125} \right)^3 = (5\sqrt{5})^3 = 125 * 5\sqrt{5} = 625\sqrt{5}.

Putting it all together: (64125)32=5126255.\left( \frac{64}{125} \right)^{\frac{3}{2}} = \frac{512}{625\sqrt{5}}.

After simplification, if needed, or if left as is, the answer could also be approximated. However, simplifying is not necessary initially.

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