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17. y is directly proportional to the square root of t - Edexcel - GCSE Maths - Question 18 - 2022 - Paper 1

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17. y is directly proportional to the square root of t. y = 15 when t = 9. t is inversely proportional to the cube of x. t = 8 when x = 2. Find a formul... show full transcript

Worked Solution & Example Answer:17. y is directly proportional to the square root of t - Edexcel - GCSE Maths - Question 18 - 2022 - Paper 1

Step 1

Finding the relationship for y in terms of t

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Answer

Since y is directly proportional to the square root of t, we can express this as:

y=kty = k \sqrt{t}

where k is a constant. Given that y = 15 when t = 9, we can substitute these values to find k:

15=k915 = k \sqrt{9}

This simplifies to:

15=k315 = k \cdot 3

Therefore, we find:

k=153=5k = \frac{15}{3} = 5

Thus, the equation becomes:

y=5ty = 5 \sqrt{t}

Step 2

Finding the relationship for t in terms of x

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Answer

Since t is inversely proportional to the cube of x, we can express this relationship as:

t=mx3t = \frac{m}{x^3}

for some constant m. Given that t = 8 when x = 2, substituting these values gives us:

8=m(2)38 = \frac{m}{(2)^3}

This simplifies to:

8=m88 = \frac{m}{8}

Thus, we find:

m=64m = 64

So we can say that:

t=64x3t = \frac{64}{x^3}

Step 3

Combining the two equations

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Answer

Now we have both expressions for y and t. We can substitute the value of t found from the second part into the first equation:

y=5ty = 5 \sqrt{t}

Replacing t:

y=564x3y = 5 \sqrt{\frac{64}{x^3}}

This simplifies to:

y=58x3/2y = 5 \cdot \frac{8}{x^{3/2}}

Thus, we can write:

y=40x3/2y = \frac{40}{x^{3/2}}

This is the final formula for y in terms of x in its simplest form.

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