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For the start of a method of simplifications, \(x^2 + 2x + 1 = (x + 1)^2 = 2^2 + 2y^2 = 2^{2y} = 2^{2y}\) - Edexcel - GCSE Maths - Question 3 - 2022 - Paper 1

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Question 3

For-the-start-of-a-method-of-simplifications,--\(x^2-+-2x-+-1-=-(x-+-1)^2-=-2^2-+-2y^2-=-2^{2y}-=-2^{2y}\)-Edexcel-GCSE Maths-Question 3-2022-Paper 1.png

For the start of a method of simplifications, \(x^2 + 2x + 1 = (x + 1)^2 = 2^2 + 2y^2 = 2^{2y} = 2^{2y}\). SC B1 for answer of 6 or \(x^2 + 4y\) scored.

Worked Solution & Example Answer:For the start of a method of simplifications, \(x^2 + 2x + 1 = (x + 1)^2 = 2^2 + 2y^2 = 2^{2y} = 2^{2y}\) - Edexcel - GCSE Maths - Question 3 - 2022 - Paper 1

Step 1

For the start of a method of simplifications

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Answer

To begin simplifying the given expression, we recognize that:

  1. The expression (x^2 + 2x + 1) can be factored as ((x + 1)^2).

  2. Next, the term (2^2 + 2y^2) can be expressed using the properties of exponents as (2^{2y}), resulting in:

    ((x+1)2)=22+2y2=22y\left( (x + 1)^2 \right) = 2^{2} + 2y^2 = 2^{2y}

  3. The end result of the expression simplifies down to (2^{2y}). To score the additional point (SC B1), we can also accept an answer of 6 or (x^2 + 4y) based on acceptable forms through marks allocation.

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