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The diagram shows triangle ABC - Edexcel - GCSE Maths - Question 7 - 2019 - Paper 1

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Question 7

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The diagram shows triangle ABC. ADB is a straight line. the size of angle DCB : the size of angle ACD = 2 : 1 Work out the size of angle BDC.

Worked Solution & Example Answer:The diagram shows triangle ABC - Edexcel - GCSE Maths - Question 7 - 2019 - Paper 1

Step 1

Find angle ACD

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Answer

To find angle ACD, first note that the angles around point D must sum to 180°. Therefore, we can write:

extAngleACD=180°75°51°=54° ext{Angle ACD} = 180° - 75° - 51° = 54°

Thus, angle ACD is 54°.

Step 2

Use the ratio to find angle DCB

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Answer

The ratio of angle DCB to angle ACD is given as 2:1. Let the size of angle DCB be 2x and the size of angle ACD be x:

extAngleDCB=2x ext{Angle DCB} = 2x extAngleACD=x ext{Angle ACD} = x

Given that angle ACD is 54°, we can set up the equation:

x=54°x = 54°

Thus, substituting this back, we find:

extAngleDCB=2(54°)=108° ext{Angle DCB} = 2(54°) = 108°.

Step 3

Calculate angle BDC

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Answer

Now to find angle BDC, we again apply the angles around point D:

extAngleBDC=180°(extAngleDCB+extAngleACD) ext{Angle BDC} = 180° - ( ext{Angle DCB} + ext{Angle ACD})

Substituting the values we have:

extAngleBDC=180°(108°+54°)=180°162°=18°. ext{Angle BDC} = 180° - (108° + 54°) = 180° - 162° = 18°.

Therefore, the size of angle BDC is 18°.

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