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C is a circle with centre the origin - Edexcel - GCSE Maths - Question 1 - 2020 - Paper 2

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C is a circle with centre the origin. A tangent to C passes through the points (–20, 0) and (0, 10) Work out an equation of C. You must show all your working.

Worked Solution & Example Answer:C is a circle with centre the origin - Edexcel - GCSE Maths - Question 1 - 2020 - Paper 2

Step 1

Find the gradient of the tangent

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Answer

To find the gradient of the tangent, we use the two given points (-20, 0) and (0, 10).

The formula for the gradient (m) between two points (x1, y1) and (x2, y2) is:

m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}

Substituting in our points:

m=1000(20)=1020=12m = \frac{10 - 0}{0 - (-20)} = \frac{10}{20} = \frac{1}{2}

Step 2

Find the angle between the tangent and the x-axis

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Answer

To find the angle (θ) that the tangent makes with the x-axis, we use the tangent function:

tan(θ)=m\tan(θ) = m

Substituting the value of m:

θ=tan1(12)θ = \tan^{-1}\left(\frac{1}{2}\right)

Step 3

Equation of the tangent

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Answer

Using the gradient-point form of the equation of a line, we can express the equation of the tangent line as:

yy1=m(xx1)y - y_1 = m(x - x_1)

Using the point (0, 10):

y10=12(x0)y - 10 = \frac{1}{2}(x - 0)

This can be simplified to:

y=12x+10y = \frac{1}{2}x + 10

Step 4

Equation of the circle

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Answer

The equation of a circle with center at the origin (0,0) is given by:

x2+y2=r2x^2 + y^2 = r^2

To find the radius (r), we can use the distance from the center (0,0) to a point on the tangent which is at (0, 10):

r=(00)2+(100)2=100=10r = \sqrt{(0 - 0)^2 + (10 - 0)^2} = \sqrt{100} = 10

Hence, the equation of the circle is:

x2+y2=102x^2 + y^2 = 10^2

This simplifies to:

x2+y2=100x^2 + y^2 = 100

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