For a complete method to find prime factors, it could be shown on a complete factor tree with no more than one error of division by prime factors with no more than one error - Edexcel - GCSE Maths - Question 1 - 2022 - Paper 1
Question 1
For a complete method to find prime factors, it could be shown on a complete factor tree with no more than one error of division by prime factors with no more than o... show full transcript
Worked Solution & Example Answer:For a complete method to find prime factors, it could be shown on a complete factor tree with no more than one error of division by prime factors with no more than one error - Edexcel - GCSE Maths - Question 1 - 2022 - Paper 1
Step 1
For a complete method to find prime factors, it could be shown on a complete factor tree with no more than one error of division by prime factors with no more than one error.
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Answer
To find the prime factors of the expression x2−9, we begin by recognizing it as a difference of squares:
x2−9=(x−3)(x+3)
Next, we can factor the individual components if applicable. In this case, neither x−3 nor x+3 can be factored further into prime factors unless specific values of x are provided.
Step 2
For complete factorization, e.g., 2, 2, 5, 5.
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Answer
The complete factorization for the expression can be expressed in terms of its prime factors. Since x2−9 evaluates to the product of two linear terms, we can focus on the coefficients if they were numeric. Here, the coefficients of any numerical constants would be expressed similarly if needed. The final expression retains the factors (x−3) and (x+3) as prime factors of this polynomial.
Step 3
For $x^2 - 9$
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Answer
Thus, the complete factorization of x2−9 is:
x2−9=(x−3)(x+3)