1. Simplify:
(a) $m' \times m^n$
(b) Simplify: $(5mp)^{y}$
(c) Simplify: \( \frac{32q^2r^{4}}{4q^{r}} \) - Edexcel - GCSE Maths - Question 2 - 2018 - Paper 2

Question 2

1. Simplify:
(a) $m' \times m^n$
(b) Simplify: $(5mp)^{y}$
(c) Simplify: \( \frac{32q^2r^{4}}{4q^{r}} \)
Worked Solution & Example Answer:1. Simplify:
(a) $m' \times m^n$
(b) Simplify: $(5mp)^{y}$
(c) Simplify: \( \frac{32q^2r^{4}}{4q^{r}} \) - Edexcel - GCSE Maths - Question 2 - 2018 - Paper 2
Simplify: $m' \times m^n$

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To simplify the expression m′×mn, we apply the property of exponents that states when multiplying like bases, we add the exponents:
m′×mn=m1+n
Thus, the simplified form is mn+1.
Simplify: $(5mp)^{y}$

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For the expression (5mp)y, we use the power of a product rule, which states that (ab)n=anbn. Therefore, we have:
(5mp)y=5ymypy
This means the simplified expression is 5ymypy.
Simplify: \( \frac{32q^2r^{4}}{4q^{r}} \)

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To simplify the fraction ( \frac{32q^2r^{4}}{4q^{r}} ), we first simplify the coefficients and then the variable terms:
- Coefficients: ( \frac{32}{4} = 8 )
- Variable terms: Since we have ( q^{2} \div q^{r} ), we apply the rule ( a^{m} \div a^{n} = a^{m-n} ):
- If ( r = 0 ): ( q^{2-0} = q^{2} )
- If ( r = 1 ): ( q^{2-1} = q^{1} )
- If ( r = 2 ): ( q^{2-2} = q^{0} = 1 )
- Continue as needed depending on the context.
- So, for the simplified expression, it can be stated as:
8q2−rr4
This gives us the final simplified form as ( 8q^{2-r} r^{4} ).
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