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A hot air balloon is descending - Edexcel - GCSE Maths - Question 20 - 2020 - Paper 2

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A hot air balloon is descending. The height of the balloon n minutes after it starts to descend is h_n metres. The height of the balloon (n + 1) minutes after it sta... show full transcript

Worked Solution & Example Answer:A hot air balloon is descending - Edexcel - GCSE Maths - Question 20 - 2020 - Paper 2

Step 1

Substituting values

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Answer

From the problem, we know that:

  • At 09:15, the height of the balloon is 1200 metres when n = 0 (h_0).
  • At 09:16, the height of the balloon is 1040 metres when n = 1 (h_1).

Let’s substitute into the equation:

h_{1} = K h_{0} + 20

Substituting the known values: 1040 = K × 1200 + 20.

Step 2

Finding K

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Answer

Rearranging the equation gives: 1040 - 20 = K × 1200 1020 = K × 1200

Now, solve for K: K = \frac{1020}{1200} = 0.85.

Step 3

Finding height at 09:17

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Answer

Now that we have K, we can find the height at 09:17 (n = 2). Using the previous height (h_1 = 1040 metres):

h_{2} = K h_{1} + 20 h_{2} = 0.85 × 1040 + 20 = 884 + 20 = 904 metres.

Step 4

Finding height at 09:18

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Answer

Now, we find the height at 09:18 (n = 3). Using the height from 09:17:

h_{3} = K h_{2} + 20 h_{3} = 0.85 × 904 + 20 = 768.4 + 20 = 788.4 metres.

Thus, the height of the balloon at 09:18 is approximately 788.4 metres.

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