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Let $ℝ$ be the set of all odd numbers less than 30; $A = \{3, 9, 15, 21, 27\}$ $B = \{5, 15, 25\}$ (a) Complete the Venn diagram to represent this information - Edexcel - GCSE Maths - Question 1 - 2017 - Paper 3

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Let-$ℝ$-be-the-set-of-all-odd-numbers-less-than-30;--$A-=-\{3,-9,-15,-21,-27\}$--$B-=-\{5,-15,-25\}$--(a)-Complete-the-Venn-diagram-to-represent-this-information-Edexcel-GCSE Maths-Question 1-2017-Paper 3.png

Let $ℝ$ be the set of all odd numbers less than 30; $A = \{3, 9, 15, 21, 27\}$ $B = \{5, 15, 25\}$ (a) Complete the Venn diagram to represent this information. A... show full transcript

Worked Solution & Example Answer:Let $ℝ$ be the set of all odd numbers less than 30; $A = \{3, 9, 15, 21, 27\}$ $B = \{5, 15, 25\}$ (a) Complete the Venn diagram to represent this information - Edexcel - GCSE Maths - Question 1 - 2017 - Paper 3

Step 1

Complete the Venn diagram

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Answer

To complete the Venn diagram, we first identify the universal set of odd numbers less than 30:

R={1,3,5,7,9,11,13,15,17,19,21,23,25,27,29}ℝ = \{1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29\}

Now, we organize the numbers based on sets A and B:

  • Set A: {3, 9, 15, 21, 27}
  • Set B: {5, 15, 25}

Next, we determine the elements in the intersections and unique portions of the sets:

  • The intersection (ABA \cap B): 15
  • Elements only in A: {3, 9, 21, 27}
  • Elements only in B: {5, 25}

Thus, we fill the Venn Diagram:

  • In set A, place 3, 9, 21, 27 and in the overlap with B, place 15. In set B, place 5 and 25.

Step 2

What is the probability that the number is in the set A ∪ B?

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Answer

To find the probability that a randomly chosen number is in the set ABA \cup B, we first need to identify the elements of ABA \cup B:

AB={3,5,9,15,21,25,27}A \cup B = \{3, 5, 9, 15, 21, 25, 27\}

Next, we count the total number of elements in ABA \cup B:

Number of elements in ABA \cup B: 7

Now, we calculate the total number of elements in the universal set R:

Number of elements in R: 15

Finally, we can compute the probability:

P(AB)=Number of elements in ABTotal number of elements in R=715P(A \cup B) = \frac{\text{Number of elements in } A \cup B}{\text{Total number of elements in } ℝ} = \frac{7}{15}

Thus, the probability is 715\frac{7}{15}.

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