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Parents Pricing Home GCSE Edexcel Maths Probability 10 (a) Simplify \( \left( \frac{1}{m} \right)^{y} \)
(b) Simplify \( \frac{8(k - 4)}{(k - 4)^{2}} \)
(c) Simplify \( (3n^{2}w^{2})^{3} \)
10 (a) Simplify \( \left( \frac{1}{m} \right)^{y} \)
(b) Simplify \( \frac{8(k - 4)}{(k - 4)^{2}} \)
(c) Simplify \( (3n^{2}w^{2})^{3} \) - Edexcel - GCSE Maths - Question 11 - 2020 - Paper 2 Question 11
View full question 10 (a) Simplify \( \left( \frac{1}{m} \right)^{y} \)
(b) Simplify \( \frac{8(k - 4)}{(k - 4)^{2}} \)
(c) Simplify \( (3n^{2}w^{2})^{3} \)
View marking scheme Worked Solution & Example Answer:10 (a) Simplify \( \left( \frac{1}{m} \right)^{y} \)
(b) Simplify \( \frac{8(k - 4)}{(k - 4)^{2}} \)
(c) Simplify \( (3n^{2}w^{2})^{3} \) - Edexcel - GCSE Maths - Question 11 - 2020 - Paper 2
Simplify \( \left( \frac{1}{m} \right)^{y} \) Only available for registered users.
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To simplify ( \left( \frac{1}{m} \right)^{y} ), we apply the power of a fraction rule, which states that ( \left( \frac{a}{b} \right)^{n} = \frac{a^{n}}{b^{n}} ). Thus, we have:
[
\left( \frac{1}{m} \right)^{y} = \frac{1^{y}}{m^{y}} = \frac{1}{m^{y}}.
]
Simplify \( \frac{8(k - 4)}{(k - 4)^{2}} \) Only available for registered users.
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The expression can be simplified by canceling common factors in the numerator and denominator:
[
\frac{8(k - 4)}{(k - 4)^{2}} = \frac{8}{k - 4}, \ k \neq 4.
]
Simplify \( (3n^{2}w^{2})^{3} \) Only available for registered users.
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For this expression, we apply the rule ( (ab)^{n} = a^{n}b^{n} ) and also handle the power of a power rule ( (a^{m})^{n} = a^{mn} ):
[
(3n^{2}w^{2})^{3} = 3^{3}(n^{2})^{3}(w^{2})^{3} = 27n^{6}w^{6}.
]
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