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There are only blue pens, green pens and red pens in a box - Edexcel - GCSE Maths - Question 4 - 2017 - Paper 3

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There are only blue pens, green pens and red pens in a box. The ratio of the number of blue pens to the number of green pens is 2 : 5. The ratio of the number of g... show full transcript

Worked Solution & Example Answer:There are only blue pens, green pens and red pens in a box - Edexcel - GCSE Maths - Question 4 - 2017 - Paper 3

Step 1

Determine ratios

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Answer

Let the number of blue pens be represented as 2x2x, the number of green pens as 5x5x, and the number of red pens as yy.

From the second ratio, the number of green pens to the number of red pens is given as 4:14 : 1, which can be written as 5x:y=4:15x : y = 4 : 1. Thus, we have:

5x=4y5x = 4y

From this, we can express yy in terms of xx:

y=5x4.y = \frac{5x}{4}.

Step 2

Find total number of pens and set constraints

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Answer

Adding the number of each type of pen, we get the total number of pens in the box:

Total=2x+5x+y=7x+y.Total = 2x + 5x + y = 7x + y.

Substituting yy from earlier:

Total=7x+5x4=28x4+5x4=33x4.Total = 7x + \frac{5x}{4} = \frac{28x}{4} + \frac{5x}{4} = \frac{33x}{4}.

Since the total number of pens must be less than 100, we set up the inequality:

33x4<100.\frac{33x}{4} < 100.

Step 3

Solve for x

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Answer

To find the maximum permissible value of xx, we multiply both sides of the inequality by 4:

33x<40033x < 400

Dividing both sides by 33 gives:

x<4003312.12.x < \frac{400}{33} \approx 12.12.

Since xx must be a whole number, the largest integer value for xx is 12.

Step 4

Calculate greatest possible number of red pens

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Answer

Using x=12x = 12, we substitute back to find the number of red pens:

y=5(12)4=15.y = \frac{5(12)}{4} = 15.

Thus, the greatest possible number of red pens in the box is 15.

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