Photo AI

2 $$v^2 = u^2 + 2as$$ $u = 12$ $a = -3$ $s = 18$ (a) Work out a value of $v$ - Edexcel - GCSE Maths - Question 3 - 2018 - Paper 1

Question icon

Question 3

2--$$v^2-=-u^2-+-2as$$--$u-=-12$--$a-=--3$--$s-=-18$--(a)-Work-out-a-value-of-$v$-Edexcel-GCSE Maths-Question 3-2018-Paper 1.png

2 $$v^2 = u^2 + 2as$$ $u = 12$ $a = -3$ $s = 18$ (a) Work out a value of $v$. (b) Make $s$ the subject of $$v^2 = u^2 + 2as$$ (Total for Question 2 is 4 marks... show full transcript

Worked Solution & Example Answer:2 $$v^2 = u^2 + 2as$$ $u = 12$ $a = -3$ $s = 18$ (a) Work out a value of $v$ - Edexcel - GCSE Maths - Question 3 - 2018 - Paper 1

Step 1

Work out a value of v.

96%

114 rated

Answer

To find the value of vv, we can substitute the given values into the equation:

  1. Substitute the values: v2=122+2×(−3)×18v^2 = 12^2 + 2 \times (-3) \times 18
  2. Calculate each part:
    • 122=14412^2 = 144
    • The term (2 \times (-3) \times 18 = -108)
  3. Combine the results:
    v2=144−108v^2 = 144 - 108
    v2=36v^2 = 36
  4. Take the square root to find vv:
    v=36v = \sqrt{36}
    v=6v = 6
    Thus, the value of vv is 6.

Step 2

Make s the subject of v^2 = u^2 + 2as

99%

104 rated

Answer

To make ss the subject of the equation, follow these steps:

  1. Start with the original equation:
    v2=u2+2asv^2 = u^2 + 2as
  2. Subtract u2u^2 from both sides:
    v2−u2=2asv^2 - u^2 = 2as
  3. Divide both sides by 2a2a:
    s=v2−u22as = \frac{v^2 - u^2}{2a}
    Thus, the expression for ss in terms of vv, uu, and aa is:
    s=v2−u22as = \frac{v^2 - u^2}{2a}

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;