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9. $T = rac{w}{ ext{sqrt}(d)}$ $w = 5.6 imes 10^5$ d = 1.4 imes 10^4$ (a) Work out the value of $T$ - Edexcel - GCSE Maths - Question 12 - 2018 - Paper 3

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Question 12

9.-$T-=--rac{w}{-ext{sqrt}(d)}$--$w-=-5.6--imes-10^5$--d-=-1.4--imes-10^4$--(a)-Work-out-the-value-of-$T$-Edexcel-GCSE Maths-Question 12-2018-Paper 3.png

9. $T = rac{w}{ ext{sqrt}(d)}$ $w = 5.6 imes 10^5$ d = 1.4 imes 10^4$ (a) Work out the value of $T$. Give your answer in standard form correct to 3 signific... show full transcript

Worked Solution & Example Answer:9. $T = rac{w}{ ext{sqrt}(d)}$ $w = 5.6 imes 10^5$ d = 1.4 imes 10^4$ (a) Work out the value of $T$ - Edexcel - GCSE Maths - Question 12 - 2018 - Paper 3

Step 1

Work out the value of T.

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Answer

To calculate the value of TT, we substitute the values of ww and dd into the formula:

T = rac{5.6 imes 10^5}{ ext{sqrt}(1.4 imes 10^4)}

First, compute the square root of dd:

extsqrt(1.4imes104)=extsqrt(1.4)imesextsqrt(104)=extsqrt(1.4)imes102 ext{sqrt}(1.4 imes 10^4) = ext{sqrt}(1.4) imes ext{sqrt}(10^4) = ext{sqrt}(1.4) imes 10^2

Using a calculator, we find that extsqrt(1.4)extisapproximately1.183 ext{sqrt}(1.4) ext{ is approximately } 1.183. Therefore:

extsqrt(1.4imes104)extisapproximately1.183imes100=118.3 ext{sqrt}(1.4 imes 10^4) ext{ is approximately } 1.183 imes 100 = 118.3

Now, substituting back into the equation for TT:

T = rac{5.6 imes 10^5}{118.3} ext{ which is approximately } 4.73 imes 10^3

Correct to 3 significant figures, we have:

Textis4.73imes103T ext{ is } 4.73 imes 10^3

Step 2

Explain why.

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Answer

Lottie's statement is incorrect. While both ww and dd increase, it is important to consider how TT is affected by these changes. The formula shows TT is inversely proportional to the square root of dd:

Textincreasesasdextdecreases,andconversely,Textdecreasesasdextincreases.T ext{ increases as } d ext{ decreases, and conversely, } T ext{ decreases as } d ext{ increases.}

Since dd increases by 5%, the resulting effect on TT may outweigh the increase in ww. To confirm this mathematically, we can determine the new value of TT after increasing ww and dd:

New w=5.6imes105imes1.1w = 5.6 imes 10^5 imes 1.1 (10% increase), and New d=1.4imes104imes1.05d = 1.4 imes 10^4 imes 1.05 (5% increase). We'll see how these values influence the overall calculation of TT.

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